Compassionate
  • Compassionate
Quick question
Mathematics
  • Stacey Warren - Expert brainly.com
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chestercat
  • chestercat
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zzr0ck3r
  • zzr0ck3r
quick would be having it in the topic \(\uparrow\)
Compassionate
  • Compassionate
\[\frac{1}{x} = \frac{x - 1}8 - \frac{x}{4} \] My first step would be \[\frac{x-1}{8} - \frac{x \times 2}{4 \times 2}\]
Compassionate
  • Compassionate
Didn't want to put more than one line of LaTeX in the subject and make it freeze up on me.

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zzr0ck3r
  • zzr0ck3r
I would multiply everything by \(8x\)
Astrophysics
  • Astrophysics
\[\huge \frac{ a }{ b } \pm \frac{ c }{ d } \implies \frac{ ad \pm bc }{ bd }\] pretty much with all fractions
Astrophysics
  • Astrophysics
I like your style zz
zzr0ck3r
  • zzr0ck3r
:)
Compassionate
  • Compassionate
\[\frac{4(x - 1) - 8x}{32} \]
Astrophysics
  • Astrophysics
That works
Astrophysics
  • Astrophysics
You can now cross multiply with the left side if you like
Compassionate
  • Compassionate
\[4x - 4 - 8x/32 = 1/x\]
Compassionate
  • Compassionate
I get it. So when adding or subtracting, we can use the ab + bd/ad rule, and when multiplying, we can cross multiply, and when dividing we can take the recipricol?
Astrophysics
  • Astrophysics
Yeah sort of, but know what kind of algebraic rules are going on, when we cross multiply for example we're just multiplying both sides by 32 and x, so yes reciprocal. :)
Astrophysics
  • Astrophysics
I mean this rule isn't anything special, it's just as you would do fractions regularly, finding common denominator..etc
zzr0ck3r
  • zzr0ck3r
In general it is a good idea to learn the following trick \[\dfrac{1}{a}+\dfrac{1}{b}=\dfrac{1}{c}\\ abc\dfrac{1}{a}+abc\dfrac{1}{b}=abc\dfrac{1}{c}\\ bc+ac=ab\] When we have fractions, it is easy to clear the denominators when we have an equals sign!
Astrophysics
  • Astrophysics
Hehe yeah, I love that
Astrophysics
  • Astrophysics
Especially with partial fractions
Compassionate
  • Compassionate
Yes. Clearing fractions. I understand. I'm just brushing up on my skills.
zzr0ck3r
  • zzr0ck3r
word

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