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Not a single bit. Now, toss some y = mx + b at me, and we'll talk.

yes

Yeah \(C_n\) usually denotes complete graphs on \(n\) vertices.

For the first equation, simplest case is \(C_3=K_3\)...

ok that is true

*second equation

oh so do they want a solution for each relation

all these equations are not like suppsoed to be solved together?

that would make my life so much easier T_T

thank you for the help!

Happy to help!

hmm C_x=K_y,z

im wondering if all
C_2n = K_n,n would be a solution to this

oh right so C_4=k2,2 only one

P2=K1,1?

Yup

Actually, there's more than just that one...

\(K_{2,1}\) is path

Yeah I'd missed that one. As well with \(K_{1,2}\).

okay yep

i got K_4=W3 only one
and K_2=K1,1 for the last one

yeah that makes sense to me