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calculate the area by integration and divide by 4 |dw:1443087401475:dw|
which will give you a time weighted average |dw:1443087484413:dw|
So the answer would be 2?
dunno let me integrate ....
mmm, don't fancy all those decimals but the the machine should get it right this is the integral http://www.wolframalpha.com/input/?i=int_%7Bt%3D0%7D%5E%7B4%7D+%28+0.1729t+%2B+0.1522t%5E2+%E2%88%92+0.0374t%5E3%29+dt and that blue rectangle i drew was just for illustration, it does not purport to be an actual solution
I'm getting two with a few different decimal combinations.. none are correct. ugh
the integral is there for you to check against..... the machine does the indefinite integral as well as the definite so you can nail it properly then as i said you are looking for a time-weighted average what's curious is that the graph goes back to zero at \(t \approx 5\) whereas you are asked for the average over \(0
okay I plugged in my intergrals & got 1.19892 but that didn't work UGH