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anonymous

  • one year ago

The volume V, in liters, of air in the lungs during a four-second respiratory cycle is approximated by the model V = 0.1729t + 0.1522t2 − 0.0374t3, where t is the time in seconds. Approximate the average volume of air in the lungs during one cycle. (Round your answer to four decimal places.)

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  1. IrishBoy123
    • one year ago
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    calculate the area by integration and divide by 4 |dw:1443087401475:dw|

  2. IrishBoy123
    • one year ago
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    which will give you a time weighted average |dw:1443087484413:dw|

  3. anonymous
    • one year ago
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    So the answer would be 2?

  4. IrishBoy123
    • one year ago
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    dunno let me integrate ....

  5. IrishBoy123
    • one year ago
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    mmm, don't fancy all those decimals but the the machine should get it right this is the integral http://www.wolframalpha.com/input/?i=int_%7Bt%3D0%7D%5E%7B4%7D+%28+0.1729t+%2B+0.1522t%5E2+%E2%88%92+0.0374t%5E3%29+dt and that blue rectangle i drew was just for illustration, it does not purport to be an actual solution

  6. anonymous
    • one year ago
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    I'm getting two with a few different decimal combinations.. none are correct. ugh

  7. IrishBoy123
    • one year ago
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    the integral is there for you to check against..... the machine does the indefinite integral as well as the definite so you can nail it properly then as i said you are looking for a time-weighted average what's curious is that the graph goes back to zero at \(t \approx 5\) whereas you are asked for the average over \(0<t<4\) but i suppose it is just a model

  8. anonymous
    • one year ago
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    okay I plugged in my intergrals & got 1.19892 but that didn't work UGH

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