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(-2, ? ) im sorry this is a new concept for me

Put that into the equation to get
\(y = a(x -2)^2+2\)

make sense so far?

because it is maximum, wont that make it a negative cooridinate or does that not apply here?

okay, i dont know how to plug in the points in runs through, im not really sure about that part

and yes, i was looking at my chart wrong, i see now that the a is whats supposed to be negative

a is our maximum value which is 2, but its negative? so -2?

a is not the maximum value. The y-coordinate of the vertex is the maximum value.

ohhh ok, my bad

|dw:1443061442308:dw|

so the final answer is \[y=2(x-2)^2-2\]

so how does a=2 ?

no, it's not 2
\(0=a(3−2)^2+2\)
\(0=a + 2\)
\(-2=a\)