I need help understanding constants

- DarkBlueChocobo

I need help understanding constants

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- DarkBlueChocobo

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- DarkBlueChocobo

and i need to experiment using numbers for a b and c when the other two are constants

- DarkBlueChocobo

@Data_LG2

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## More answers

- anonymous

but what are you trying to do though? finding the relationship of those variables?..
can you take a screen shot of the whole question ?

- zepdrix

Is t representing a variable, time perhaps?
And the others are constants?

- zepdrix

So what type of translations are you trying to make? :)
reflections?
shifts?
change in amplitude/asymptote?

- zepdrix

To translate left or right,
you would replace \(\large\rm t\) with something.
Or just make an adjustment to t, however you want to look at it.
If I want to shift the entire function 2 units to the right, I would replace t with t-2.

- zepdrix

Example:\[\Huge\rm 3e^{-2e^{-2\color{orangered}{t}}}\qquad\to\qquad 3e^{-2e^{-2\color{orangered}{(t-2)}}}\]

- DarkBlueChocobo

They be wanting me to find what values b tranlate function right

- zepdrix

Oh ya I guess b translates it :)
Didn't notice lol
that's neat

- DarkBlueChocobo

loool

- DarkBlueChocobo

So would be just plug in b for something?

- DarkBlueChocobo

thats greater than 0 I mean

- zepdrix

Ya, here are some examples:
https://www.desmos.com/calculator/jtq3mi46x6

- zepdrix

I dunno what kind of numbers you're looking for :3 maybe those are too big

- DarkBlueChocobo

so for this example -2 is the is the constant for c?

- zepdrix

a=1, c=2 according to your formula.

- DarkBlueChocobo

explain please?

- zepdrix

\[\Huge\rm ae^{-be^{-\color{orangered}{c}t}}\qquad\to\qquad ae^{-be^{-\color{orangered}{2}t}}\]The negative is part of your formula, it's not part of the c.

- zepdrix

If we plugged in c=-2, we would get this instead,\[\Huge\rm ae^{-be^{-\color{orangered}{c}t}}\qquad\to\qquad ae^{-be^{-\color{orangered}{(-2)}t}}\]

- DarkBlueChocobo

so question then is that recorded inthe graph in desmos? Thats like saying positive 2 t?

- DarkBlueChocobo

Sorry I asking so many questions trying to figure out more than just solve kinda deal

- zepdrix

So this is what I graphed:
Green a=1, b=2, c=2
Purple a=1, b=4, c=2
Black a=1, b=12, c=2

- zepdrix

I think that's what you mentioned earlier, yes?
That b and c must be greater than zero.
So I was plugging in positive numbers, hence they are all negative because of the formula getting it to them.

- zepdrix

Think of it like one big snake.
They picked up the snake and moved him 2 to the right, and set him down.
They didn't stretch or distort in any way.
They simply every point of the function 2 units to the right.

- zepdrix

They simply moved* every point of the function 2 units to the right.

- zepdrix

But yes, you can use the origin as a point of reference.
The green line, b=2, has a nice point (0, 0.135)
This point on the purple line, b=4, has moved to (0.346, 0.135)
So I should be careful the way I say that :(
It's not a straight up `linear transformation`.
It isn't actually moving it 2 units like I was saying before.

- zepdrix

Very weird function +_+

- zepdrix

XD

- zepdrix

Well it's unclear `how much` b is affecting the function.
But we can, at the very least, say that that:
the larger b gets, the further the function moves to the right, ya?

- zepdrix

I'm not sure what else we can say about it XD lol

- zepdrix

Yes.
a usually stands for "amplitude", it makes the function "grow" faster.
But yes, it looks like it's affecting our horizontal asymptote here.
a=2 would allow the function to grow to double it's ending size.

- zepdrix

No. lol
you just sent me my own graph back 0_o

- zepdrix

You can't copy/paste the link at the top of the site.
You have to log-in, and then use the `share graph` button :)
it's a green button that shows up after you log in

- zepdrix

The b and c values didn't change as you adjusted your a values.
Good! :)

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