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DarkBlueChocobo
 one year ago
I need help understanding constants
DarkBlueChocobo
 one year ago
I need help understanding constants

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DarkBlueChocobo
 one year ago
Best ResponseYou've already chosen the best response.0dw:1443061144471:dw

DarkBlueChocobo
 one year ago
Best ResponseYou've already chosen the best response.0and i need to experiment using numbers for a b and c when the other two are constants

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but what are you trying to do though? finding the relationship of those variables?.. can you take a screen shot of the whole question ?

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2Is t representing a variable, time perhaps? And the others are constants?

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2So what type of translations are you trying to make? :) reflections? shifts? change in amplitude/asymptote?

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2To translate left or right, you would replace \(\large\rm t\) with something. Or just make an adjustment to t, however you want to look at it. If I want to shift the entire function 2 units to the right, I would replace t with t2.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2Example:\[\Huge\rm 3e^{2e^{2\color{orangered}{t}}}\qquad\to\qquad 3e^{2e^{2\color{orangered}{(t2)}}}\]

DarkBlueChocobo
 one year ago
Best ResponseYou've already chosen the best response.0They be wanting me to find what values b tranlate function right

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2Oh ya I guess b translates it :) Didn't notice lol that's neat

DarkBlueChocobo
 one year ago
Best ResponseYou've already chosen the best response.0So would be just plug in b for something?

DarkBlueChocobo
 one year ago
Best ResponseYou've already chosen the best response.0thats greater than 0 I mean

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2Ya, here are some examples: https://www.desmos.com/calculator/jtq3mi46x6

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2I dunno what kind of numbers you're looking for :3 maybe those are too big

DarkBlueChocobo
 one year ago
Best ResponseYou've already chosen the best response.0so for this example 2 is the is the constant for c?

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2a=1, c=2 according to your formula.

DarkBlueChocobo
 one year ago
Best ResponseYou've already chosen the best response.0explain please?

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2\[\Huge\rm ae^{be^{\color{orangered}{c}t}}\qquad\to\qquad ae^{be^{\color{orangered}{2}t}}\]The negative is part of your formula, it's not part of the c.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2If we plugged in c=2, we would get this instead,\[\Huge\rm ae^{be^{\color{orangered}{c}t}}\qquad\to\qquad ae^{be^{\color{orangered}{(2)}t}}\]

DarkBlueChocobo
 one year ago
Best ResponseYou've already chosen the best response.0so question then is that recorded inthe graph in desmos? Thats like saying positive 2 t?

DarkBlueChocobo
 one year ago
Best ResponseYou've already chosen the best response.0Sorry I asking so many questions trying to figure out more than just solve kinda deal

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2So this is what I graphed: Green a=1, b=2, c=2 Purple a=1, b=4, c=2 Black a=1, b=12, c=2

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2I think that's what you mentioned earlier, yes? That b and c must be greater than zero. So I was plugging in positive numbers, hence they are all negative because of the formula getting it to them.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2Think of it like one big snake. They picked up the snake and moved him 2 to the right, and set him down. They didn't stretch or distort in any way. They simply every point of the function 2 units to the right.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2They simply moved* every point of the function 2 units to the right.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2But yes, you can use the origin as a point of reference. The green line, b=2, has a nice point (0, 0.135) This point on the purple line, b=4, has moved to (0.346, 0.135) So I should be careful the way I say that :( It's not a straight up `linear transformation`. It isn't actually moving it 2 units like I was saying before.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2Very weird function +_+

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2Well it's unclear `how much` b is affecting the function. But we can, at the very least, say that that: the larger b gets, the further the function moves to the right, ya?

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2I'm not sure what else we can say about it XD lol

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2Yes. a usually stands for "amplitude", it makes the function "grow" faster. But yes, it looks like it's affecting our horizontal asymptote here. a=2 would allow the function to grow to double it's ending size.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2No. lol you just sent me my own graph back 0_o

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2You can't copy/paste the link at the top of the site. You have to login, and then use the `share graph` button :) it's a green button that shows up after you log in

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2The b and c values didn't change as you adjusted your a values. Good! :)
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