## DarkBlueChocobo one year ago I need help understanding constants

1. DarkBlueChocobo

|dw:1443061144471:dw|

2. DarkBlueChocobo

and i need to experiment using numbers for a b and c when the other two are constants

3. DarkBlueChocobo

@Data_LG2

4. anonymous

but what are you trying to do though? finding the relationship of those variables?.. can you take a screen shot of the whole question ?

5. zepdrix

Is t representing a variable, time perhaps? And the others are constants?

6. zepdrix

So what type of translations are you trying to make? :) reflections? shifts? change in amplitude/asymptote?

7. zepdrix

To translate left or right, you would replace $$\large\rm t$$ with something. Or just make an adjustment to t, however you want to look at it. If I want to shift the entire function 2 units to the right, I would replace t with t-2.

8. zepdrix

Example:$\Huge\rm 3e^{-2e^{-2\color{orangered}{t}}}\qquad\to\qquad 3e^{-2e^{-2\color{orangered}{(t-2)}}}$

9. DarkBlueChocobo

They be wanting me to find what values b tranlate function right

10. zepdrix

Oh ya I guess b translates it :) Didn't notice lol that's neat

11. DarkBlueChocobo

loool

12. DarkBlueChocobo

So would be just plug in b for something?

13. DarkBlueChocobo

thats greater than 0 I mean

14. zepdrix

Ya, here are some examples: https://www.desmos.com/calculator/jtq3mi46x6

15. zepdrix

I dunno what kind of numbers you're looking for :3 maybe those are too big

16. DarkBlueChocobo

so for this example -2 is the is the constant for c?

17. zepdrix

a=1, c=2 according to your formula.

18. DarkBlueChocobo

19. zepdrix

$\Huge\rm ae^{-be^{-\color{orangered}{c}t}}\qquad\to\qquad ae^{-be^{-\color{orangered}{2}t}}$The negative is part of your formula, it's not part of the c.

20. zepdrix

If we plugged in c=-2, we would get this instead,$\Huge\rm ae^{-be^{-\color{orangered}{c}t}}\qquad\to\qquad ae^{-be^{-\color{orangered}{(-2)}t}}$

21. DarkBlueChocobo

so question then is that recorded inthe graph in desmos? Thats like saying positive 2 t?

22. DarkBlueChocobo

Sorry I asking so many questions trying to figure out more than just solve kinda deal

23. zepdrix

So this is what I graphed: Green a=1, b=2, c=2 Purple a=1, b=4, c=2 Black a=1, b=12, c=2

24. zepdrix

I think that's what you mentioned earlier, yes? That b and c must be greater than zero. So I was plugging in positive numbers, hence they are all negative because of the formula getting it to them.

25. zepdrix

Think of it like one big snake. They picked up the snake and moved him 2 to the right, and set him down. They didn't stretch or distort in any way. They simply every point of the function 2 units to the right.

26. zepdrix

They simply moved* every point of the function 2 units to the right.

27. zepdrix

But yes, you can use the origin as a point of reference. The green line, b=2, has a nice point (0, 0.135) This point on the purple line, b=4, has moved to (0.346, 0.135) So I should be careful the way I say that :( It's not a straight up linear transformation. It isn't actually moving it 2 units like I was saying before.

28. zepdrix

Very weird function +_+

29. zepdrix

XD

30. zepdrix

Well it's unclear how much b is affecting the function. But we can, at the very least, say that that: the larger b gets, the further the function moves to the right, ya?

31. zepdrix

I'm not sure what else we can say about it XD lol

32. zepdrix

Yes. a usually stands for "amplitude", it makes the function "grow" faster. But yes, it looks like it's affecting our horizontal asymptote here. a=2 would allow the function to grow to double it's ending size.

33. zepdrix

No. lol you just sent me my own graph back 0_o

34. zepdrix

You can't copy/paste the link at the top of the site. You have to log-in, and then use the share graph button :) it's a green button that shows up after you log in

35. zepdrix

The b and c values didn't change as you adjusted your a values. Good! :)