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@IrishBoy123 I see you're viewing my question. Might you be able/willing to help me?

sure

OKay, cool. So like I said, I can't figure out what the question is trying to get me to do.

Yes, that's correct.

ok
let me crunch some numbers then

OK
is my answer closer to the website's?
we can deal with the rest in a minute

|dw:1443088796660:dw|

Yes. to three sig figs, it is \[v _{r} = 16.0\]. But like I said, we already knew that one.

what they wany when they say radial velocity is this
|dw:1443088879804:dw|

Good morning all you amazing people!!!!!

Yeah, I see it.

so are we ready to do it?

|dw:1443089158375:dw|

Sure. It's not what I was asking for, but sure, let's do this.

OKay.

does that make sense to you?

You have me up until you have \[t = \frac{ <-4, 1> }{ \sqrt{17} }\].
Where'd you get that?

*had

|dw:1443091705155:dw|

i gave you a medal!

thanks Pat

So I don't even use v at all except for when I'm solving for it?

not for resolving acceleration into its components, no

But I thought acceleration was by definition, the derivative of velocity.

Also, it's worth mentioning that I'm not given the magnitude of the acceleration.

So the dot product you describe wouldn't actually work in this case.

\(\frac{32}{\sqrt{17}}\) and \(\frac{8}{\sqrt{17}}\)

Thanks, by the way, for you patience in helping me out.

Well, thanks again. I'm going to close this thread now.