anonymous
  • anonymous
The three vertices of a triangle drawn on a complex plane are represented by 0 + 0i, 4 + 0i, and 0+ 3i. The length of the hypotenuse is (a-4 or b-5) units, and the area of the triangle is (a-6, b-12) square units
Algebra
katieb
  • katieb
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anonymous
  • anonymous
anonymous
  • anonymous
are you supposed to find a and b?
anonymous
  • anonymous
i suppose the length of the hypotenuse can only be 4 or 5 and the are of the triangle can only be 6 or 12

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anonymous
  • anonymous
If you draw the points you get this|dw:1443106559597:dw|
anonymous
  • anonymous
im still soooo confused algebra is my worst subject!
anonymous
  • anonymous
Once you have the points they make a 3-4-5 triangle. The two legs are 3 and 4, so the hypotenuse has to be 5. Or you could use the pythagorean theorem a² + b² = c² 3² + 4² = c² 25 = c² c = 5
anonymous
  • anonymous
so my answers would be 5 and?
anonymous
  • anonymous
Find the area of the triangle. A = ½bh = ½(3)(4)
anonymous
  • anonymous
i dont know how to do that...
anonymous
  • anonymous
what's 3*4?
anonymous
  • anonymous
then divide that by 2
anonymous
  • anonymous
so 6?
anonymous
  • anonymous
yes
anonymous
  • anonymous
yay! thank you

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