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anonymous

  • one year ago

The three vertices of a triangle drawn on a complex plane are represented by 0 + 0i, 4 + 0i, and 0+ 3i. The length of the hypotenuse is (a-4 or b-5) units, and the area of the triangle is (a-6, b-12) square units

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  1. anonymous
    • one year ago
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    @peachpi @paki

  2. anonymous
    • one year ago
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    are you supposed to find a and b?

  3. anonymous
    • one year ago
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    i suppose the length of the hypotenuse can only be 4 or 5 and the are of the triangle can only be 6 or 12

  4. anonymous
    • one year ago
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    If you draw the points you get this|dw:1443106559597:dw|

  5. anonymous
    • one year ago
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    im still soooo confused algebra is my worst subject!

  6. anonymous
    • one year ago
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    Once you have the points they make a 3-4-5 triangle. The two legs are 3 and 4, so the hypotenuse has to be 5. Or you could use the pythagorean theorem a² + b² = c² 3² + 4² = c² 25 = c² c = 5

  7. anonymous
    • one year ago
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    so my answers would be 5 and?

  8. anonymous
    • one year ago
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    Find the area of the triangle. A = ½bh = ½(3)(4)

  9. anonymous
    • one year ago
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    i dont know how to do that...

  10. anonymous
    • one year ago
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    what's 3*4?

  11. anonymous
    • one year ago
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    then divide that by 2

  12. anonymous
    • one year ago
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    so 6?

  13. anonymous
    • one year ago
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    yes

  14. anonymous
    • one year ago
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    yay! thank you

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spraguer (Moderator)
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