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anonymous
 one year ago
The three vertices of a triangle drawn on a complex plane are represented by 0 + 0i, 4 + 0i, and 0+ 3i.
The length of the hypotenuse is (a4 or b5) units, and the area of the triangle is (a6, b12) square units
anonymous
 one year ago
The three vertices of a triangle drawn on a complex plane are represented by 0 + 0i, 4 + 0i, and 0+ 3i. The length of the hypotenuse is (a4 or b5) units, and the area of the triangle is (a6, b12) square units

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0are you supposed to find a and b?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i suppose the length of the hypotenuse can only be 4 or 5 and the are of the triangle can only be 6 or 12

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0If you draw the points you get thisdw:1443106559597:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im still soooo confused algebra is my worst subject!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Once you have the points they make a 345 triangle. The two legs are 3 and 4, so the hypotenuse has to be 5. Or you could use the pythagorean theorem a² + b² = c² 3² + 4² = c² 25 = c² c = 5

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so my answers would be 5 and?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Find the area of the triangle. A = ½bh = ½(3)(4)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i dont know how to do that...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0then divide that by 2
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