anonymous
  • anonymous
You reach into a bag of coins and withdraw two coins. What is the probability you withdrew a nickel and then a dime if the bag held five pennies, ten nickels and four dimes ?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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sleepyhead314
  • sleepyhead314
mmm I'm not the best at probability, but I know that we should definitely first find out how many coins there are in total so 5 pennies + 10 nickles + 4 dimes = [how many coins?]
anonymous
  • anonymous
19 coins
sleepyhead314
  • sleepyhead314
good :) then the chance of getting a nickel on the first try is [number of nickles] / [total number of coins] = ?

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More answers

anonymous
  • anonymous
Even though they separate the coins into categories, they are still in one group, so combine everything except the nickels and dimes.
anonymous
  • anonymous
20 / 171
sleepyhead314
  • sleepyhead314
whoa there number of nickles = 10 total number of coins = 19 10 / 19 is the chance of pulling a nickel on the first try
sleepyhead314
  • sleepyhead314
then after we take the nickel out we are left with a total of \(18\) coins total right?
anonymous
  • anonymous
yes
sleepyhead314
  • sleepyhead314
then the chance of pulling a dime next is [number of dimes] / [new total number of coins] = ?
anonymous
  • anonymous
1.8
sleepyhead314
  • sleepyhead314
oh oh oh oh right I was taking one step at a time but the 20 / 171 answer you gave before is correct ^_^"
anonymous
  • anonymous
okay thank you

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