You reach into a bag of coins and withdraw two coins. What is the probability you withdrew a nickel and then a dime if the bag held five pennies, ten nickels and four dimes ?

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You reach into a bag of coins and withdraw two coins. What is the probability you withdrew a nickel and then a dime if the bag held five pennies, ten nickels and four dimes ?

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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mmm I'm not the best at probability, but I know that we should definitely first find out how many coins there are in total so 5 pennies + 10 nickles + 4 dimes = [how many coins?]
19 coins
good :) then the chance of getting a nickel on the first try is [number of nickles] / [total number of coins] = ?

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Other answers:

Even though they separate the coins into categories, they are still in one group, so combine everything except the nickels and dimes.
20 / 171
whoa there number of nickles = 10 total number of coins = 19 10 / 19 is the chance of pulling a nickel on the first try
then after we take the nickel out we are left with a total of \(18\) coins total right?
yes
then the chance of pulling a dime next is [number of dimes] / [new total number of coins] = ?
1.8
oh oh oh oh right I was taking one step at a time but the 20 / 171 answer you gave before is correct ^_^"
okay thank you

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