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anonymous

  • one year ago

You reach into a bag of coins and withdraw two coins. What is the probability you withdrew a nickel and then a dime if the bag held five pennies, ten nickels and four dimes ?

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  1. sleepyhead314
    • one year ago
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    mmm I'm not the best at probability, but I know that we should definitely first find out how many coins there are in total so 5 pennies + 10 nickles + 4 dimes = [how many coins?]

  2. anonymous
    • one year ago
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    19 coins

  3. sleepyhead314
    • one year ago
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    good :) then the chance of getting a nickel on the first try is [number of nickles] / [total number of coins] = ?

  4. anonymous
    • one year ago
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    Even though they separate the coins into categories, they are still in one group, so combine everything except the nickels and dimes.

  5. anonymous
    • one year ago
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    20 / 171

  6. sleepyhead314
    • one year ago
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    whoa there number of nickles = 10 total number of coins = 19 10 / 19 is the chance of pulling a nickel on the first try

  7. sleepyhead314
    • one year ago
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    then after we take the nickel out we are left with a total of \(18\) coins total right?

  8. anonymous
    • one year ago
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    yes

  9. sleepyhead314
    • one year ago
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    then the chance of pulling a dime next is [number of dimes] / [new total number of coins] = ?

  10. anonymous
    • one year ago
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    1.8

  11. sleepyhead314
    • one year ago
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    oh oh oh oh right I was taking one step at a time but the 20 / 171 answer you gave before is correct ^_^"

  12. anonymous
    • one year ago
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    okay thank you

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