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anonymous

  • one year ago

Help please!!!!

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  1. james1769
    • one year ago
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    what do u need help with

  2. james1769
    • one year ago
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    yes im thinkin

  3. james1769
    • one year ago
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    taking note

  4. james1769
    • one year ago
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    can u add the exponents?

  5. james1769
    • one year ago
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    add them

  6. anonymous
    • one year ago
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    Can you help?

  7. james1769
    • one year ago
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    yes im tryin my best

  8. james1769
    • one year ago
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    @XxPrisillaXx

  9. james1769
    • one year ago
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    it would be 4^3=2 i think

  10. james1769
    • one year ago
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    srry if i am no help

  11. anonymous
    • one year ago
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    You are but I was seeing a few examples of how to do this, and that doesn't look right to me.

  12. james1769
    • one year ago
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    okay what do u think it is

  13. anonymous
    • one year ago
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    @welshfella

  14. welshfella
    • one year ago
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    4 = 2^2 so 4^-1 = 2^(-2)

  15. welshfella
    • one year ago
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    |dw:1443113530353:dw|

  16. welshfella
    • one year ago
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    as the bases are both 2 we can say -2x = x + 3

  17. welshfella
    • one year ago
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    so just solve that equation and you have your answer

  18. anonymous
    • one year ago
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    oh okay, but I have to make a table for these two equations with integer values between 3 and -3

  19. welshfella
    • one year ago
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    oh so you just plug in values form -3 to 3 so if x = -3 4^(--3) = 4^3 = 64 and 2^(-3+3) = 2^0 = 1

  20. welshfella
    • one year ago
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    when x = -1 you'll find they both have the value 1/4

  21. welshfella
    • one year ago
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    - that is the solution of the above equation

  22. welshfella
    • one year ago
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    did you understand how i got 64 and 1 for when x = -3?

  23. anonymous
    • one year ago
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    Yes I do sir.

  24. welshfella
    • one year ago
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    ok then lets try x = -2 4^-x = 4^(-(-2) = 4^2 = 16 2^(x+3) = 2^(-2+3) = 2^1 = 2

  25. welshfella
    • one year ago
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    note when the power becomes negative you convert to 1 / the postive value for example 4^-3 = 1/4^3 = 1/64

  26. anonymous
    • one year ago
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    oh okay I got it now.

  27. anonymous
    • one year ago
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    Thank you very much!

  28. welshfella
    • one year ago
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    yw . You can do it. You are fearless!

  29. anonymous
    • one year ago
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    @welshfella can you tell me how to do the rest and if any of mine are incorrect.

  30. anonymous
    • one year ago
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    @Nnesha , @welshfella can you tell me if I did any of these wrong and how to solve the rest.

  31. anonymous
    • one year ago
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    @Nnesha

  32. welshfella
    • one year ago
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    yes the top 3 are correct what about value of 2^(x+3) when x = 0?

  33. welshfella
    • one year ago
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    sorry gotta go

  34. anonymous
    • one year ago
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    @campbell_st

  35. anonymous
    • one year ago
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    @mathstudent55

  36. anonymous
    • one year ago
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    I can't figure out the rest.

  37. campbell_st
    • one year ago
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    if you have \[2^{x + 3}\] when x = 0 you have \[2^{0 + 3} = 2^3 = \] just calculate the answer now

  38. campbell_st
    • one year ago
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    correct... and there are a few errors looking at \[4^{-x}\] when x = -3 its \[4^{-(-3)} = 4^3 = \] calculate a value..

  39. anonymous
    • one year ago
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    okay so would it be 64 right? And it has to be in a fraction form right?

  40. campbell_st
    • one year ago
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    that's correct... the column 4^(-x) you start with 64 and then divide by 4 |dw:1443134411663:dw| snf 2^{x + 3) you are multiplying the previous answer by 2 hope it makes sense

  41. campbell_st
    • one year ago
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    |dw:1443134586802:dw| that should help

  42. campbell_st
    • one year ago
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    looks perfect

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is replying to Can someone tell me what button the professor is hitting...

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