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anonymous

  • one year ago

WILL MEDAL

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  1. anonymous
    • one year ago
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    @Hero Can you help?

  2. anonymous
    • one year ago
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    \[(4^{2})^{3} 4^{0}\]

  3. anonymous
    • one year ago
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    any number raised to 0 is one.

  4. anonymous
    • one year ago
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    when a power is raised to another power, you must multiply the two powers by each other.

  5. anonymous
    • one year ago
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    the answer i think it is \[4\times ^{24}\]

  6. anonymous
    • one year ago
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    how did you get that?

  7. Hero
    • one year ago
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    @firedmeup are you familar with order of operations? Perform what is in parentheses first.

  8. anonymous
    • one year ago
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    nvm mind that

  9. anonymous
    • one year ago
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    i am familiar with the order of operations yes...

  10. anonymous
    • one year ago
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    so multiply the exponents. 2x3. = \[4^{6}\]

  11. anonymous
    • one year ago
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    yes

  12. anonymous
    • one year ago
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    what would 4^6 get you?

  13. anonymous
    • one year ago
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    24

  14. anonymous
    • one year ago
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    I meant 4 raised to the 6th power.

  15. anonymous
    • one year ago
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    oh

  16. anonymous
    • one year ago
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    4 raised to the 6th power is 4,096

  17. anonymous
    • one year ago
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    yes sorry i had to do something

  18. anonymous
    • one year ago
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    it's fine. Do you know what the next step would be?

  19. anonymous
    • one year ago
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    4 to the 0 power is 1 so \[4^{6}\times4^{0}\] ?

  20. anonymous
    • one year ago
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    remember what I said before: any number raised to zero gives you 1. so you would have \[4^{6} 1\]

  21. anonymous
    • one year ago
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    ok. i just missed a step.. oops

  22. anonymous
    • one year ago
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    so the answer is 4,096

  23. anonymous
    • one year ago
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    ?

  24. anonymous
    • one year ago
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    yes! Do you understand now?

  25. anonymous
    • one year ago
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    yes. but i need to simplify to a fraction..

  26. anonymous
    • one year ago
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    ok

  27. anonymous
    • one year ago
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    Thankyou soooo much

  28. anonymous
    • one year ago
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    your welcome :)

  29. anonymous
    • one year ago
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    what did you need help with a fraction

  30. anonymous
    • one year ago
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    the answers are 0 4 to the 6th 4 to the 7th and 4 to the 24th

  31. anonymous
    • one year ago
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    It would be 4 to the 6th because that is the only one that gives the correct answer.

  32. anonymous
    • one year ago
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    i haveit its 4 to the 6th.

  33. anonymous
    • one year ago
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    yep

  34. anonymous
    • one year ago
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    lol thanks!

  35. anonymous
    • one year ago
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    your welcome.

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spraguer (Moderator)
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