anonymous
  • anonymous
Calculus help please see attached
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
anonymous
  • anonymous
the problem is y= 4th rooth (x^3-9x-1) *x^5
klimenkov
  • klimenkov
Simplify the numerator and add two fractions. \[5 x^4\sqrt[4]{x^3-9x-1}=\frac{5 x^4 \left(x^3-9x-1\right) ^ \frac{1}{4} \, \left(4(x^3-9x-1)^{\frac{ 3 }{ 4 }}\right) }{ 4(x^3-9x-1)^{\frac{ 3 }{ 4 }} }\]

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anonymous
  • anonymous
I don't see how you came to multiply the numerator by [4(x^3-9x-1)^(3/4) or how all simplifying that adds up to 23x^7-189x^5-20x^4 perhaps you could brake the steps down for me, thanks

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