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anonymous
 one year ago
Did I get this right?
Factor: a^3y+1
I got
(a^y+1)(a^y1)
anonymous
 one year ago
Did I get this right? Factor: a^3y+1 I got (a^y+1)(a^y1)

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ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.0(a^y+1)(a^y1) multiply them and see if you get back the original expression

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Give me one second. :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I think you will get : [a(^y)^2  1^2] after multiplying (a^y+1)(a^y1)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Well, it appears that I don't know how to do it. Can someone perhaps explain. @ganeshie8

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Hmm it is really simple just remember this equation: a^3y+1 is a sum of cubes. a^3+b^3= (a+b) (a^2ab+b^2) So, a^3y+1= (a^y+1)(a^2ya+1)
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