Johan14th
  • Johan14th
how to solve for the inverse of f(x)= 3/x-2 y= 3/y-2 ???? what would the next step be?
Mathematics
schrodinger
  • schrodinger
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jim_thompson5910
  • jim_thompson5910
is the original function \[\Large f(x) = \frac{3}{x-2}\] OR \[\Large f(x) = \frac{3}{x}-2\]
Johan14th
  • Johan14th
Oh sorry about the lack of parenthesis it would be the first one.
jim_thompson5910
  • jim_thompson5910
ok thanks

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jim_thompson5910
  • jim_thompson5910
y= 3/(x-2) x= 3/(y-2) ... swap x and y, now solve for y x(y-2)= 3 x*y-2x = 3 x*y = 3+2x y = (3+2x)/x
jim_thompson5910
  • jim_thompson5910
So the inverse is \[\Large f^{-1}(x) = \frac{3+2x}{x}\]
Johan14th
  • Johan14th
Oh okay that you that makes a lot of sense now. :)

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