## anonymous one year ago how to solve for the inverse of f(x)= 3/x-2 y= 3/y-2 ???? what would the next step be?

1. jim_thompson5910

is the original function $\Large f(x) = \frac{3}{x-2}$ OR $\Large f(x) = \frac{3}{x}-2$

2. anonymous

Oh sorry about the lack of parenthesis it would be the first one.

3. jim_thompson5910

ok thanks

4. jim_thompson5910

y= 3/(x-2) x= 3/(y-2) ... swap x and y, now solve for y x(y-2)= 3 x*y-2x = 3 x*y = 3+2x y = (3+2x)/x

5. jim_thompson5910

So the inverse is $\Large f^{-1}(x) = \frac{3+2x}{x}$

6. anonymous

Oh okay that you that makes a lot of sense now. :)