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Destinyyyy

  • one year ago

Help with two problems..

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  1. Destinyyyy
    • one year ago
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    Given f(x)= 3+2/x and g(x)= 1/x find f_g, f-g, fg, and f/g. Determine the domain for each function.

  2. Destinyyyy
    • one year ago
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    I only need help with the last one. f/g. I got 3x+2/1 the system is telling me its correct but not fully simplified.

  3. Destinyyyy
    • one year ago
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    @Nnesha

  4. Destinyyyy
    • one year ago
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    @IrishBoy123

  5. Nnesha
    • one year ago
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    f(x) divide by g(x) \[\huge\rm \frac{ \frac{ 3+2 }{ x } }{ \frac{ 1 }{ x } }\] now solve

  6. Nnesha
    • one year ago
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    combine like terms first and then multiply top with the reciprocal of the bottom fraction

  7. Destinyyyy
    • one year ago
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    Sorry the site wouldnt load to let me back in..

  8. Destinyyyy
    • one year ago
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    Huh? I have 3x+2/ 1

  9. Nnesha
    • one year ago
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    \(\color{blue}{\text{Originally Posted by}}\) @Destinyyyy Given f(x)= 3+2/x and g(x)= 1/x find f_g, f-g, fg, and f/g. Determine the domain for each function. \(\color{blue}{\text{End of Quote}}\) f(x) is 3+2/1

  10. Destinyyyy
    • one year ago
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    ?

  11. Destinyyyy
    • one year ago
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    The 1 is under 3x+2

  12. Destinyyyy
    • one year ago
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    I need to simplify that further so how.

  13. Nnesha
    • one year ago
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    well the question u posted above is f(x) = 3+2/x

  14. Nnesha
    • one year ago
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    please rewrite f(x) and f(x) function

  15. Destinyyyy
    • one year ago
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    What? f(x)= 3+ 2/x g(x)= 1/x some*

  16. Destinyyyy
    • one year ago
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    the x is only under the 2.

  17. Destinyyyy
    • one year ago
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    3+ 2/x over 1/x * x/x = 3x+2 all over 1

  18. Nnesha
    • one year ago
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    alright \[\huge\rm \frac{ 3+\frac{ 2 }{ x } }{ \frac{ 1 }{ x } }\] equal \[\frac{\frac{ 3x+2 }{ x } }{ \frac{ 1 }{ x } } = \frac{ 3x+2 }{ x } \times \frac{ x }{ 1 } = 3x+2\] that's it

  19. Nnesha
    • one year ago
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    that's simplified !

  20. Destinyyyy
    • one year ago
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    Alright. Thank you. For f(x)= 2x-5 and g(x)= 4x^2 -4 D. (g*f)(1)

  21. Nnesha
    • one year ago
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    according to the previous post i guess * means compose like (g o f)(1) so first find f(1) substitute x for 1 into f(x) function or in other words you have to find g(f(1))

  22. Nnesha
    • one year ago
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    but if it's a multiplication sign then it would be f(1) times g(1)

  23. Destinyyyy
    • one year ago
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    Yes the o thing.

  24. Nnesha
    • one year ago
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    ye thats what i asked n the previous post (f * g)(x) isn't same as (f o g)(x) ^multiplication ^substitution

  25. Nnesha
    • one year ago
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    ( g o f)(1) = g -compose -f of 1

  26. Destinyyyy
    • one year ago
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    Yeah sorry about that. Its super tiny on my screen so I assumed it was *

  27. Nnesha
    • one year ago
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    its okay :=)

  28. Destinyyyy
    • one year ago
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  29. Nnesha
    • one year ago
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    so for this question find (g o f )(1) = g(f(1)) substitute x for 1 into f(x) function then plugin the result into g(x) function

  30. Destinyyyy
    • one year ago
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    The picture shows the example I have.

  31. Nnesha
    • one year ago
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    alright so in the example first they solvved g(f(x) and then sub x for 1

  32. Destinyyyy
    • one year ago
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    So 4(2x-5)^2 -4 ?

  33. Nnesha
    • one year ago
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    looks good

  34. Destinyyyy
    • one year ago
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    That all turns into 16x^2 -80x +96

  35. Destinyyyy
    • one year ago
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    And I just plug 1 in for x correct?

  36. Nnesha
    • one year ago
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    alright i'll trust the calculator yes right now replace x with 1

  37. Destinyyyy
    • one year ago
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    Final answer 32

  38. Nnesha
    • one year ago
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    right

  39. Destinyyyy
    • one year ago
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    Thank you.

  40. Nnesha
    • one year ago
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    yw

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