A handy man knows from experience that his 29-foot ladder rests in its most stable position when the distance of its base from a wall is 1 foot farther than the height it reaches up the wall. 1) how far up a wall does this ladder reach? 2) how far should the base be from the wall? 3) If the man needs to reach a window 25feet high on the wall, how far from the wall should he place the base of the ladder?
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Did you draw a figure, and label what you know ?
can you draw a figure ?
How about this
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I know how to make the drawing the problem is i do not know how to solve the problem
Using this info:
the distance of its base from a wall is 1 foot farther than the height it reaches up the wall.
and if we call the (unknown) height x, what is the distance along the ground ? (i.e. the bottom of the triangle) ?
i need help with part 2 and 3 of the question im not sure how to solve the problem and come up with the answer
yes, that is good.
You have a right triangle. Do you know pythagoras formula?
can you write down the formula, but using the sizes in the drawing ? i.e. legs are x and (x+1) and the hypotenuse is 29
I HAVE ALREADY COMPLETED that. I need help with part 2 and 3 of the question.
what did you get ?
the height of the wall is 20ft
yes, so that means in the picture x=20
the base of the triangle is x+1
so you can figure out answer to 2)
3) If the man needs to reach a window 25feet high on the wall, how far from the wall should he place the base of the ladder?
label a new figure
I would write down pythagoras using those values
\[ x^2 +25^2 = 29^2 \]
can you solve for x ?
is x 14?
it's not exact. you need a calculator. or type into google
you get 14.6969...
Do they ask you to round the answer ?