Geometry help please?

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Geometry help please?

Mathematics
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i only need help with the first and 2nd one please!
@Owlcoffee @xxDragoonxx @happy_to_help if any of you guys knows this stuff pleas help!

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Other answers:

2c.36 2d.96
yeah i already knew those 2 thanks, do you know 2a and 2b or 1? @happy_to_help
No soryy.
i already figured out 2) all i need is 1 and 3 @Owlcoffee
To find the ordered pair of "L' " you'll have to multiply the coordinates of "L" by 1/4
so what does that mean exactly lol, sry im not good at geometry
do you know what #3 is?
Like this, if L has coordinates (-4,-6), we can find the ordered pair in the new hexagon by doing the multiplication of 1/4 on the x and the y coordinates of the point, which means: \[L'([\frac{ 1 }{ 4 }(-4)],[\frac{ 1 }{ 4 } -6]) \]
Sorry, it has to multiply: \[L'[(\frac{ 1 }{ 4 }(-4)),\frac{ 1 }{ 4 }(-6)]\]
ok , so what do i do next?
operate the multiplications.
i have no idea what youre saying im sorry lol i just started taking geometry and i dont get any of it, do you mean solve that equation that you gave me?
It's no equation, it's the representation of the dilated point, it would look like this: \[L'(\frac{ (-4) }{ 4 }, \frac{ (-6) }{ 4 })\]
oh ok gotcha, so how do we find the ordered pair
L' is the ordered pair.

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