anonymous one year ago Geometry help please?

1. anonymous

2. anonymous

i only need help with the first and 2nd one please!

3. anonymous

@Owlcoffee @xxDragoonxx @happy_to_help if any of you guys knows this stuff pleas help!

4. happy_to_help

2c.36 2d.96

5. anonymous

yeah i already knew those 2 thanks, do you know 2a and 2b or 1? @happy_to_help

6. happy_to_help

No soryy.

7. anonymous

i already figured out 2) all i need is 1 and 3 @Owlcoffee

8. Owlcoffee

To find the ordered pair of "L' " you'll have to multiply the coordinates of "L" by 1/4

9. anonymous

so what does that mean exactly lol, sry im not good at geometry

10. anonymous

do you know what #3 is?

11. Owlcoffee

Like this, if L has coordinates (-4,-6), we can find the ordered pair in the new hexagon by doing the multiplication of 1/4 on the x and the y coordinates of the point, which means: $L'([\frac{ 1 }{ 4 }(-4)],[\frac{ 1 }{ 4 } -6])$

12. Owlcoffee

Sorry, it has to multiply: $L'[(\frac{ 1 }{ 4 }(-4)),\frac{ 1 }{ 4 }(-6)]$

13. anonymous

ok , so what do i do next?

14. Owlcoffee

operate the multiplications.

15. anonymous

i have no idea what youre saying im sorry lol i just started taking geometry and i dont get any of it, do you mean solve that equation that you gave me?

16. Owlcoffee

It's no equation, it's the representation of the dilated point, it would look like this: $L'(\frac{ (-4) }{ 4 }, \frac{ (-6) }{ 4 })$

17. anonymous

oh ok gotcha, so how do we find the ordered pair

18. Owlcoffee

L' is the ordered pair.

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