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mortonsalt

  • one year ago

Hello! I was wondering if someone can help me with this question? (Will be posted below.)

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  1. mortonsalt
    • one year ago
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    Find the limit as it approaches infinity when \[\frac{4x-1}{x} < f(x) < \frac{4x^2+3x}{x^2}\] for all x>5.

  2. anonymous
    • one year ago
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    you need to find out what x is?

  3. anonymous
    • one year ago
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    or you need the answer?

  4. mortonsalt
    • one year ago
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    Im just trying to figure out where to begin. :) Thank you!

  5. anonymous
    • one year ago
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    @welshfella

  6. anonymous
    • one year ago
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    He will help you a lot then

  7. mortonsalt
    • one year ago
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    Is it 4?

  8. anonymous
    • one year ago
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    no

  9. welshfella
    • one year ago
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    sorry cant help with this one

  10. anonymous
    • one year ago
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    lol

  11. anonymous
    • one year ago
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    is this a multiple choice question?

  12. mortonsalt
    • one year ago
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    Nope!

  13. anonymous
    • one year ago
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    ok good

  14. anonymous
    • one year ago
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    10x^2

  15. mortonsalt
    • one year ago
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    Alright, thanks!

  16. anonymous
    • one year ago
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    :D

  17. zepdrix
    • one year ago
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    Take limit of left side,\[\large\rm \lim\limits_{x\to\infty}\frac{4x-1}{x}=a\]It will approach some value. Take limit of the other side,\[\large\rm \lim\limits_{x\to\infty}\frac{4x^2+3x}{x^2}=a\]You'll find that they approach the same value! So by Squeeze Theorem: \(\large\rm f(x)\to a\) as \(\large\rm x\to\infty\). It's a little disturbing that you have strict inequalities.. those shouldn't be strict. Maybe a typo? Anyway, yes 4 sounds right! :)

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