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mortonsalt
 one year ago
Hello! I was wondering if someone can help me with this question? (Will be posted below.)
mortonsalt
 one year ago
Hello! I was wondering if someone can help me with this question? (Will be posted below.)

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mortonsalt
 one year ago
Best ResponseYou've already chosen the best response.0Find the limit as it approaches infinity when \[\frac{4x1}{x} < f(x) < \frac{4x^2+3x}{x^2}\] for all x>5.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you need to find out what x is?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0or you need the answer?

mortonsalt
 one year ago
Best ResponseYou've already chosen the best response.0Im just trying to figure out where to begin. :) Thank you!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0He will help you a lot then

welshfella
 one year ago
Best ResponseYou've already chosen the best response.0sorry cant help with this one

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0is this a multiple choice question?

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0Take limit of left side,\[\large\rm \lim\limits_{x\to\infty}\frac{4x1}{x}=a\]It will approach some value. Take limit of the other side,\[\large\rm \lim\limits_{x\to\infty}\frac{4x^2+3x}{x^2}=a\]You'll find that they approach the same value! So by Squeeze Theorem: \(\large\rm f(x)\to a\) as \(\large\rm x\to\infty\). It's a little disturbing that you have strict inequalities.. those shouldn't be strict. Maybe a typo? Anyway, yes 4 sounds right! :)
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