haleyelizabeth2017
  • haleyelizabeth2017
The area of a parking lot is 805 square meters. A car requires 5 square meters and a bus requires 32 square meters of space. There can be at most 80 vehicles parked at one time. If the cost to park a car is $2.00 and a bus is $6.00, how many buses should be in the lot to maximize income? Please no direct answers.
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
haleyelizabeth2017
  • haleyelizabeth2017
Would the first inequality be \[5c+32b \le 805\]?
Hero
  • Hero
looks right
haleyelizabeth2017
  • haleyelizabeth2017
Okay...I'm not sure what to put for the second one...\(c+b\le 80\)?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

Hero
  • Hero
why did you write 805 Instead of 80 ?
haleyelizabeth2017
  • haleyelizabeth2017
there are 805 square meters in the parking lot.
haleyelizabeth2017
  • haleyelizabeth2017
Shoot...typo, sorry.
Hero
  • Hero
Wait. Yoo mean 85
haleyelizabeth2017
  • haleyelizabeth2017
I made a typo...I meant 805, my bad
Hero
  • Hero
Assuming your inequalities are correct, what do you think would be the next step?
haleyelizabeth2017
  • haleyelizabeth2017
Don't I need a third inequality? For prices?
haleyelizabeth2017
  • haleyelizabeth2017
oh wait...no...I use the prices to find the min/max! So f(x,y)=2c+6b?
Hero
  • Hero
Correct
haleyelizabeth2017
  • haleyelizabeth2017
Will there only be one intersection point then?
haleyelizabeth2017
  • haleyelizabeth2017
But, would max be at (65,15) so 15 buses?
Hero
  • Hero
There's a range of points Within a region that are possible, but there is only one correct pair of coordinates that will maximize the profit
Hero
  • Hero
Show we how you found that result.
haleyelizabeth2017
  • haleyelizabeth2017
I have no idea...I just chose the intersection point...I'm sorry, I'm having a hard time understanding these word problems...with only two inequalities to graph...
Hero
  • Hero
There's almost always four inequalities to graph and you usually use x and y for variables
haleyelizabeth2017
  • haleyelizabeth2017
When I dealt with the three inequalities I plugged in the intersection points into the f(x,y) function...
Hero
  • Hero
Because you also consider .\[c \ge 0\] and \[b \ge 0\]
haleyelizabeth2017
  • haleyelizabeth2017
oh.
Hero
  • Hero
but If you use x and y as variables, then you can use a platform like desmos to plot your inequalities
haleyelizabeth2017
  • haleyelizabeth2017
That's what I'm doing :)
haleyelizabeth2017
  • haleyelizabeth2017
So, the intersection points I have now are: (80, 0) (65, 15) (0, 25.16) (0,0) But we can tell already that (0,0) will not be the maximum.
haleyelizabeth2017
  • haleyelizabeth2017
It is (65,15).
haleyelizabeth2017
  • haleyelizabeth2017
f(80,0)=160 f(0, 25.16)=150.96 f(0,0)=0 f(65,15)=220
haleyelizabeth2017
  • haleyelizabeth2017
Would you mind helping me with a couple more?
Hero
  • Hero
Sure, but you seem to already know what you are doing for the Most part.
haleyelizabeth2017
  • haleyelizabeth2017
I think for one I just need it checked...not sure about the last one..
haleyelizabeth2017
  • haleyelizabeth2017
Eh I'll just post the one I need help on :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.