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Would the first inequality be \[5c+32b \le 805\]?

looks right

Okay...I'm not sure what to put for the second one...\(c+b\le 80\)?

why did you write 805 Instead of 80 ?

there are 805 square meters in the parking lot.

Shoot...typo, sorry.

Wait. Yoo mean 85

I made a typo...I meant 805, my bad

Assuming your inequalities are correct, what do you think would be the next step?

Don't I need a third inequality? For prices?

oh wait...no...I use the prices to find the min/max! So f(x,y)=2c+6b?

Correct

Will there only be one intersection point then?

But, would max be at (65,15) so 15 buses?

Show we how you found that result.

There's almost always four inequalities to graph and you usually use x and y for variables

Because you also consider .\[c \ge 0\] and \[b \ge 0\]

That's what I'm doing :)

It is (65,15).

f(80,0)=160
f(0, 25.16)=150.96
f(0,0)=0
f(65,15)=220

Would you mind helping me with a couple more?

Sure, but you seem to already know what you are doing for the Most part.

I think for one I just need it checked...not sure about the last one..

Eh I'll just post the one I need help on :)