parabolic function going down from the left through the point zero comma six and turning at approximately the point two and one half comma negative one fourth and going up through the point three comma zero and continuing towards infinity Courtesy of Texas Instruments 6 3 –2 2

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parabolic function going down from the left through the point zero comma six and turning at approximately the point two and one half comma negative one fourth and going up through the point three comma zero and continuing towards infinity Courtesy of Texas Instruments 6 3 –2 2

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Calculate the average rate of change for the given graph from x = 0 to x = 3 and select the correct answer.
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hi
The rate of change they are talking about is the slope of a secant line connecting those two points on the graph
average rate of change - slope of secant line Instantaneous rate of change - slope of a tangent line, derivative at f(a)
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good?
is this for calculus 1, or physics.. or
Alg 2
-,-
ok, when you see average rate of change, it will mean -- the slope of a line through those two given points...
Do you remember how to calculate the slope in relation to the xy-axis?
I forgot the formula
its -2 i think
Just remember, it is how much vertical change there is (y-direction) per one unit change in the x-direction\ The rise/run thing
okay i got -2
\[slope= \frac{ y _{2}-y _{1} }{ x _{2}-x _{1} }\]
Did that
looks good
OHH
THANKS MAN I LOVE YOU
ha, you get er now?
YEA
kk, goodluck
|dw:1443136923446:dw|
There ya go, no matter what curve graph there is, if they want the average rate of change, just calculate the slope of the straight line through the two endpoints

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