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ofmiceparade

  • one year ago

parabolic function going down from the left through the point zero comma six and turning at approximately the point two and one half comma negative one fourth and going up through the point three comma zero and continuing towards infinity Courtesy of Texas Instruments 6 3 –2 2

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  1. ofmiceparade
    • one year ago
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  2. ofmiceparade
    • one year ago
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    Calculate the average rate of change for the given graph from x = 0 to x = 3 and select the correct answer.

  3. ofmiceparade
    • one year ago
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    AyeEEEEEEEEEEEEE @DanJS

  4. DanJS
    • one year ago
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    hi

  5. DanJS
    • one year ago
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    The rate of change they are talking about is the slope of a secant line connecting those two points on the graph

  6. DanJS
    • one year ago
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    average rate of change - slope of secant line Instantaneous rate of change - slope of a tangent line, derivative at f(a)

  7. ofmiceparade
    • one year ago
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  8. DanJS
    • one year ago
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    good?

  9. DanJS
    • one year ago
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    is this for calculus 1, or physics.. or

  10. ofmiceparade
    • one year ago
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    Alg 2

  11. ofmiceparade
    • one year ago
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    -,-

  12. DanJS
    • one year ago
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    ok, when you see average rate of change, it will mean -- the slope of a line through those two given points...

  13. DanJS
    • one year ago
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    Do you remember how to calculate the slope in relation to the xy-axis?

  14. ofmiceparade
    • one year ago
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    I forgot the formula

  15. ofmiceparade
    • one year ago
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    its -2 i think

  16. DanJS
    • one year ago
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    Just remember, it is how much vertical change there is (y-direction) per one unit change in the x-direction\ The rise/run thing

  17. ofmiceparade
    • one year ago
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    okay i got -2

  18. DanJS
    • one year ago
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    \[slope= \frac{ y _{2}-y _{1} }{ x _{2}-x _{1} }\]

  19. ofmiceparade
    • one year ago
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    Did that

  20. DanJS
    • one year ago
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    looks good

  21. ofmiceparade
    • one year ago
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    OHH

  22. ofmiceparade
    • one year ago
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    THANKS MAN I LOVE YOU

  23. DanJS
    • one year ago
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    ha, you get er now?

  24. ofmiceparade
    • one year ago
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    YEA

  25. DanJS
    • one year ago
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    kk, goodluck

  26. DanJS
    • one year ago
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    |dw:1443136923446:dw|

  27. DanJS
    • one year ago
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    There ya go, no matter what curve graph there is, if they want the average rate of change, just calculate the slope of the straight line through the two endpoints

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