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It's the second page 17
so we're given y = mx + b, and we want to solve for b subtract mx from each side to get b by itself
I have to subtract 3x on each side
where are you getting 3 from?
It's on question 13
I thought you wanted question 17?
No I need help on all of them
ok, let's start with 13 then
so we have 3x + 5y = 30, so yes, we would start by subtracting 3x from each side
5y = 30 - 3x, do you know where to go from there?
subtract 3x on both sides
right, so that gives us 5y = 30 - 3x, now keep going
like that ?
uh, not quite. we want y by itself, but we have 5y, so we divide everything by 5
5y = 30 - 3x y = (30-3x)/5
The answer is 5.4
uh, not quite, you just stop when you get y = (30-3x)/5
the question asked us to get y, and we got y, so y = (30-3x)/5 is our final answer
is that suppose to be dividing before 5
For the next the first step is 6y=360-24x
I thinks I did it wrong
because it says for x
yeah, so we want x by itself start by subtracting 6y from both sides
24x=6y-360 like that <-
almost 24x = 360 - 6y now we want x by itself, so we divide both sides by 24 x = (360-6y)/24
Do I just put the equation or do I have to solve it
that's it, our answer is x = (360-6y)/24
The next one is hard
start by multiplying both sides by 32
It starts 1280-80d=32c
good, now subtract 1280 from both sides
Do i also subtract 1280 to 80 or 32 ?
nope, since 80 and 32 are attached to variables (letters) we leave them alone
-80d = 32c - 1280 divide both sides by -80 now
uh, not quite, remember that 32c and 1280 can't be put together because of the c -80d = 32c - 1280 d = (32c-1280)/(-80)
oh so thats the equation
I need help on question 16
multiply both sides by (9/5) first
nope, we want to multiply by (9/5) to get rid of the (5/9)
idk what would be the equation
(9/5)C = F - 32 now add 32 to both sides
I add 32 to 32 and 9/5
nope, leave the 9/5 alone since its attached to c (9/5)C + 32 = F
So the equation would be 9/5c+32=f
yes, or you can flip it around to get F = (9/5)C + 32
For the next questions is not even using numbers ?
y = mx + b subtract mx from both sides
just treat mx like a number
Is it y=(mx-b)
uh, not quite y - mx = mx + b - mx now keep going
you cancel out mx
good, so that leaves us with y - mx = b and since the question wants b by itself, we're done
b = y - mx
ok, last one Ax + By = C start by subtracting Ax from both sides
Isn't it y=c/b-a/b*x
Thank you so much sorry for bothering you all the time
almost, Y = C/B - A*x/B and don't apologize, you aren't a bother :)