12y-8 over -4? anyone?? We have to simplify the expression.

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12y-8 over -4? anyone?? We have to simplify the expression.

Algebra
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y=-2/12
(12y-8) / - 4 or 12y - (8/-4)
group multiple term numerator and denominator with parenthesis

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I meant 3y+2
remember the properties of addition of fractions \[\frac{ 12y-8 }{ -4 } = \frac{ 12y }{ -4 }-\frac{ 8 }{ -4 }\]
simplify both those fractions if possible
ok
(12/-4) *y - (8/(-4)) = -3y - (-2) = -3y+2 close
\[\frac{ 12y - 8 }{ -4 } = \frac{ 12y}{ -4 } + \frac{- 8 }{ -4 } = -3y + 2\] If you want find the Y: \[-3y + 2 = 0\]\[3y = 2\]\[y = \frac{ 2 }{ 3 }\]\[y = 1,5\]
You can not solve for anything, How do you figure you just set that = to zero?
-3y + 2 nothing to solve , simplified
Hey my friend, i just said that if he want to find the Y, he can set -3y + 2 = 0 why you so angry? lol

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