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Anikate
 one year ago
A driver in a car traveling at a speed of
75 km/h sees a cat 125 m away on the road.
How long will it take for the car to accelerate
uniformly to a stop in exactly 122 m?
Answer in units of s.
Anikate
 one year ago
A driver in a car traveling at a speed of 75 km/h sees a cat 125 m away on the road. How long will it take for the car to accelerate uniformly to a stop in exactly 122 m? Answer in units of s.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@pooja195 im new to helping

Anikate
 one year ago
Best ResponseYou've already chosen the best response.0do u know the answer??

Anikate
 one year ago
Best ResponseYou've already chosen the best response.0@DylanisNOW u know the answer??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Im trying to get @pooja195

Anikate
 one year ago
Best ResponseYou've already chosen the best response.0i thuink she offline, but do know the answer to this question??

Anikate
 one year ago
Best ResponseYou've already chosen the best response.0she appeears to be offline??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Hold on...Im trying to figure it out. Please dont rush!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@pooja195 No she isnt

Anikate
 one year ago
Best ResponseYou've already chosen the best response.0ok, do u know how to do it though?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Give me a sec please

Anikate
 one year ago
Best ResponseYou've already chosen the best response.0@pgpilot326 do u know how to do this? its a physics question

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0units are 75km/h right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Wait sorry hold on thats not it thats only 1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay do you have answer choices?

Anikate
 one year ago
Best ResponseYou've already chosen the best response.0do u havea roungh estimate of what the andswer could be??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Think of it like this. Every second the speed decreases by?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0We cant give answers...Its just help to get you to understand it!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Think of it like this. Every second the speed decreases by?

Anikate
 one year ago
Best ResponseYou've already chosen the best response.0the speed decreases by seconds(squared)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0.... @pgpilot326 can you help me help him?

Anikate
 one year ago
Best ResponseYou've already chosen the best response.0dylanis, can u just post a step by step explaination for it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Step 1:units are 75km/h

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Step 2:75km/h / 125=600m/h

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay now we are at step 3

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0if a is a constant, integrate to get velocity and again to get position. the velocity should be linear and the position a quadratic.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0since you know the initial and final speed you should be able to calc. the time

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0pgpilot should we make a equation?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0should make 2 equations... velocity and position. you'll need both.

Anikate
 one year ago
Best ResponseYou've already chosen the best response.0can you please show bothh?

Anikate
 one year ago
Best ResponseYou've already chosen the best response.0and solve with steps please?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[v \left( t \right)=v_0+at\]and\[x \left( t \right)=x_0+v_0t+\frac{ 1 }{ 2 }at^2\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0pg you are right good job btw :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0at t=0, initial speed (\(v_0\)) is 75 km/h and initial position is 0 m. at t=\(t_1\), final speed (\(v_f\)) is 0 km/h and final position is 122 m.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you need to solve for \(t_1\)

Anikate
 one year ago
Best ResponseYou've already chosen the best response.0which equation am i putting all this in??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0phone, just a minute

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[v \left( t_1 \right)=0=75 +a\cdot t_1\] \[x \left( t_1 \right)=122=0+75t_1+\frac{ 1 }{ 2 }at_1^2\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0find roots of quadratic in terms of a.

Anikate
 one year ago
Best ResponseYou've already chosen the best response.0u can handwrite it if u wish, ill prob be able to decode it

Anikate
 one year ago
Best ResponseYou've already chosen the best response.0isnt htat what we have now?? what now??

Anikate
 one year ago
Best ResponseYou've already chosen the best response.0can u show rest of steps

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0solve velocity eqn for t1 and position for t1 and equate

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0to solve for a. once you have a you can find t1

Anikate
 one year ago
Best ResponseYou've already chosen the best response.0how do u solve for t1?? there are 2 variables in the equation itself

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0from velocity: t1 = 75/a

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0use quadratic to solve the position: \[0=122+75t_1+\frac{ 1 }{ 2 }at_1^2\]for t1 in terms of a

Anikate
 one year ago
Best ResponseYou've already chosen the best response.0dw:1443143204081:dw thats as far as i can get

Anikate
 one year ago
Best ResponseYou've already chosen the best response.0can u please explain how u would do it, and go past that step

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1443143218606:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0use the quadratic formula

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1443143430909:dwthen solve for a

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you'll have to square to get rid of square root

Anikate
 one year ago
Best ResponseYou've already chosen the best response.0ok then, can u plz post work till answer?

Anikate
 one year ago
Best ResponseYou've already chosen the best response.0kinda hard to follow step by step

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0k but it will take a minute

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[122=75\left( \frac{ 75 }{ a } \right)+\frac{ a\left( 75 \right)^2 }{ 2a^2} \Rightarrow 122 =\frac{ 5625 }{ a } +\frac{ 5625 }{ 2a }\Rightarrow 244a = 11250+5625\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[a=\frac{ 5625 }{244 } \Rightarrow t_1 = \frac{ 75 }{ \frac{ 5625 }{ 244 } }=\frac{ 244 }{ 75} \text{ sec}\]

Anikate
 one year ago
Best ResponseYou've already chosen the best response.0AAH ok! I see! thanks a lot! @pgpilot326
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