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Arihangdu

  • one year ago

Iron - 59 has a half life of 45.1 ayes. How old is an iron nail if the Fe -59 content is 25% that of a new sample of iron ? Please show me all the calculation to understand.

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  1. Arihangdu
    • one year ago
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    Please help me I will give medals and fans.

  2. Vocaloid
    • one year ago
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    amount left = original amount*(1/2)^(total time/length of half-life) so plugging in our numbers, we get: .25 = (1/2)^(t/45.1) solve for t

  3. Arihangdu
    • one year ago
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    How to solve please help me

  4. Vocaloid
    • one year ago
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    .25 = (1/2)^2 so (1/2)^2 = (1/2)^(t/45.1) 2 = t/45.1 solve for t

  5. Arihangdu
    • one year ago
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    T= 45.1 x 2= 90?

  6. Arihangdu
    • one year ago
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    Right?

  7. Vocaloid
    • one year ago
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    90.2 but yeah

  8. Arihangdu
    • one year ago
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    Any formula we need to use here please?

  9. Vocaloid
    • one year ago
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    no, that's it, t = 90.2 years...

  10. Arihangdu
    • one year ago
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    Days or years ?

  11. Arihangdu
    • one year ago
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    A=Ao *m this not a decays formula ?or I confused !,

  12. Arihangdu
    • one year ago
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    Ok thank you so much for helping

  13. Arihangdu
    • one year ago
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    Please receive my appreciation.

  14. Arihangdu
    • one year ago
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    Thanks for helping me.

  15. Arihangdu
    • one year ago
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    I don't know how you do this steps .25= 1/2^t/45.1 1/2^2=1/2)^t/45.1

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