anonymous
  • anonymous
Name at least 2 different ways you can solve the equation 5^(2x+1)=25
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
LynFran
  • LynFran
exponential...and i think logs
anonymous
  • anonymous
i have one method so far, which is solving by having equal bases is that right?
LynFran
  • LynFran
5^(2x+1)=25 5^(2x+1)=5^2 so 2x+1=2 2x=2-1 x=1/2

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

LynFran
  • LynFran
yes equal base ... same as exponent
LynFran
  • LynFran
im logs also
anonymous
  • anonymous
would you solve the problem the same way with logs? or do you solve it with different steps?
LynFran
  • LynFran
\[\log _{25}(5)=(2x+1)\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.