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hpfan101
 one year ago
\[\lim_{t \rightarrow \infty}\frac{ \sqrt{t}+t^2 }{ 2tt^2 }\]
hpfan101
 one year ago
\[\lim_{t \rightarrow \infty}\frac{ \sqrt{t}+t^2 }{ 2tt^2 }\]

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hpfan101
 one year ago
Best ResponseYou've already chosen the best response.0How do I find the limit?

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.1look at the highest exponent term in the numerator and the denominator the numerator's highest exponent term is t^2 the denominator's highest exponent term is t^2 then divide numerator term/denominator term to find the limit (t^2)/(t^2) = 1 that's your limit

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.1(this only works if the exponents are the same)

hpfan101
 one year ago
Best ResponseYou've already chosen the best response.0Oh ok, thank you! That was a much easier method than how I was doing it.
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