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calculusxy
 one year ago
Question with exponents!
Question attached below...
calculusxy
 one year ago
Question with exponents! Question attached below...

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calculusxy
 one year ago
Best ResponseYou've already chosen the best response.0\[\huge \frac{ (xy^4)^{4} }{ 2x^3 \times x^2y^3 }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[(2x^3)(x^2y^2) \implies 2 \cdot x^{3+2} \cdot y^2 =~?\]

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.0i got the answer of \[\frac{ 1 }{ 2x^9y^19 }\] but the answer key says that it's negative.. i don't know why

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Alright let's check each step.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what would you get for : \(\color{#0cbb34}{\text{Originally Posted by}}\) @Jhannybean \[\large (2x^3)(x^2y^2) \implies 2 \cdot x^{3+2} \cdot y^2 =~?\] \(\color{#0cbb34}{\text{End of Quote}}\)

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.0\[\large 2x^5y^2\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Alright, and when you distribute the \(4\) power into every term in the ( ), you expand it like so: \[\large (xy^4)^{4} \implies (x)^{4} \cdot (y^4)^{4} = ~?\]

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.0\[\large x^{4} \times y^0\]

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.0which is basically like \[\large x^{4}\]

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.0\[\large \times \] do you mean this symbol? if so, it's multiplication.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0be careful, you wouldnt be adding the exponents here, you'd be multiplying them. \[\large (y^4)^{4} = y^{4( 4)}\qquad (y^4)^{4} \ne y^{44}\]

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.0i still don't understand how you got the negative...

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.0yeah or whose ever work that was posted in the 3 parts

just_one_last_goodbye
 one year ago
Best ResponseYou've already chosen the best response.0pretty fast eh? ^_^ thinking about making it a tool on OS as an extention

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0defeats the purpose of Openstudy then.

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.0can you please help me understand why it is a negative?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok cotinuing from where we left off.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I just realized theres an easier way to simplify the numerator, check this out

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Instead of expanding our numerator first, we can basically turn our entire term WITH the negative exponent into a positive one. \[\large (xy^4)^{4} \implies \dfrac{1}{(xy^4)^4}\] you see how the negatives in the numerator would go away?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So now we expand our numerator, and we get: \[\large \frac{1}{x^4y^{16}}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Now we put it over our denominator: \[\large \dfrac{\dfrac{1}{x^4y^{16}}}{2x^5y^3}\qquad \implies \qquad \dfrac{1}{2x^{4+5}y^{16+3} } \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Now whether we have the negative in the numerator OR denominator, it doesnt matter, the fraction altogether is STILL negative.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Do you follow, @calculusxy ?

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.0i am still trying to grasp this.

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.0if we have like complex fractions, then we would have to add the exponents n put it over one?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The only reason we did that, was because we treated \((xy^4)\) as like a variable... let' say all that junk \(=a\). And then... a is raised to a negative power, and how would we turn that power positive? by putting it over 1. \(a^{1} \iff \dfrac{1}{a}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So if we have a FRACTION in the numerator, and we're DIVIDING it by a term or terms in the denominator, we follow this rule: \[\dfrac{\dfrac{a}{b}}{c} \implies \frac{a}{bc}\]

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.0i have one other question..

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.0thanks for helping me understand that

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Which art are you stuck on? WE'll go from there.

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.0so this time i am getting a negative, but it says that it's a positive. \[\large \frac{ ba^0 \times a^3b^3 }{ (ab^0)^{4} }\]

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.0so i got \[\large a^7b^4\] but the answer key simply says \[\large a^7b^4\]

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.0@jim_thompson5910 it's the second expression w/ exponents.
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