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anonymous
 one year ago
Need help and an explanation on how to do this, please.
When 0.7521g of benzoic acid was burned in a calorimeter containing 1,000g of water, a temperature rise of 3.60 degrees C was observed. What is the heat capacity of the bomb calorimeter, excluding the water? The heat of combustion of benzoic acid is 26.42 kJ/g.
anonymous
 one year ago
Need help and an explanation on how to do this, please. When 0.7521g of benzoic acid was burned in a calorimeter containing 1,000g of water, a temperature rise of 3.60 degrees C was observed. What is the heat capacity of the bomb calorimeter, excluding the water? The heat of combustion of benzoic acid is 26.42 kJ/g.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Is there an equation for you to plug these numbers into?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[Q=(m)(c)(\Delta)(T)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm not too sure which one to use.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0How come we use that equation even though there isn't really a change in temperature?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It says the temperature increased 3.6 degrees C so that is the temperature change

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ah, I see. But we don't have to calculate a temperature change in this case, right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Nope! its already done for you! :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The heat capacity would be "c" in the equation?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so what i'm not really understanding is: they've given the mass (0.7521g of benzoic acid) and they've given the temperature (3.60 degrees C).. where/how do we use the 1,000g of water and the heat of combustion of benzoic acid in the question?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0If i'm correct, the water is just something thrown in there to mess you up, but Q is the 26.42

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So this would the equation 26.42= (0.7521)(c)(3.6)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0C is the heat capacity

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0would the answer be 9.76J?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I did find an explanation to this problem on yahoo answers (and i'm not doubting your way) but they got another answer and used steps i don't understand :(

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0would you like the link?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0https://answers.yahoo.com/question/index?qid=20120424181717AAxs958

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Woah. Thats a lot of work. I checked the guys bio and he is a chemistry professor so i would probably go with his answer, but I assumed that it would be the explanation I gave you. I don't understand any of that, but then again he is a professor. You could write both solutions down and then ask your teacher which one is right. If your class has been doing Specific Heat and Heat Capacity equations then I would use mine, but if that is not the case then the other guy is probably correct with is crazy math.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ha! That's how i felt :( I'll definitely ask on both because not knowing the way he did on yahoo answers means we didn't go over it in class but yours made sense as well.. even though now i'm double confused lol but thank you for your help!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i found 1 more explanation actually!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0this person did it with less math

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Q(comb) = (0.7521g)((26.42KJ/g) = 19.87KJ Q(H20) = (3.6C)(1000g)[4.184J/(gC)] = 15.062KJ Q(cal) = 19.87KJ  15.062KJ = 4.81KJ SpH = 4.81KJ/3.6C = 1.34 KJ/C

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That looks less confusing but thats above what I know

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Alright, great! Thank you.
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