anonymous
  • anonymous
Need help and an explanation on how to do this, please. When 0.7521g of benzoic acid was burned in a calorimeter containing 1,000g of water, a temperature rise of 3.60 degrees C was observed. What is the heat capacity of the bomb calorimeter, excluding the water? The heat of combustion of benzoic acid is -26.42 kJ/g.
Chemistry
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Is there an equation for you to plug these numbers into?
anonymous
  • anonymous
\[Q=(m)(c)(\Delta)(T)\]
anonymous
  • anonymous
I'm not too sure which one to use.

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More answers

anonymous
  • anonymous
How come we use that equation even though there isn't really a change in temperature?
anonymous
  • anonymous
It says the temperature increased 3.6 degrees C so that is the temperature change
anonymous
  • anonymous
Ah, I see. But we don't have to calculate a temperature change in this case, right?
anonymous
  • anonymous
Nope! its already done for you! :)
anonymous
  • anonymous
The heat capacity would be "c" in the equation?
anonymous
  • anonymous
yes!
anonymous
  • anonymous
so what i'm not really understanding is: they've given the mass (0.7521g of benzoic acid) and they've given the temperature (3.60 degrees C).. where/how do we use the 1,000g of water and the heat of combustion of benzoic acid in the question?
anonymous
  • anonymous
If i'm correct, the water is just something thrown in there to mess you up, but Q is the -26.42
anonymous
  • anonymous
So this would the equation -26.42= (0.7521)(c)(3.6)
anonymous
  • anonymous
C is the heat capacity
anonymous
  • anonymous
would the answer be -9.76J?
anonymous
  • anonymous
Thats what I got!
anonymous
  • anonymous
I did find an explanation to this problem on yahoo answers (and i'm not doubting your way) but they got another answer and used steps i don't understand :(
anonymous
  • anonymous
would you like the link?
anonymous
  • anonymous
Sure!
anonymous
  • anonymous
https://answers.yahoo.com/question/index?qid=20120424181717AAxs958
anonymous
  • anonymous
Woah. Thats a lot of work. I checked the guys bio and he is a chemistry professor so i would probably go with his answer, but I assumed that it would be the explanation I gave you. I don't understand any of that, but then again he is a professor. You could write both solutions down and then ask your teacher which one is right. If your class has been doing Specific Heat and Heat Capacity equations then I would use mine, but if that is not the case then the other guy is probably correct with is crazy math.
anonymous
  • anonymous
ha! That's how i felt :( I'll definitely ask on both because not knowing the way he did on yahoo answers means we didn't go over it in class but yours made sense as well.. even though now i'm double confused lol but thank you for your help!
anonymous
  • anonymous
i found 1 more explanation actually!
anonymous
  • anonymous
this person did it with less math
anonymous
  • anonymous
Q(comb) = (0.7521g)((-26.42KJ/g) = -19.87KJ Q(H20) = (3.6C)(1000g)[4.184J/(g-C)] = 15.062KJ Q(cal) = 19.87KJ - 15.062KJ = 4.81KJ SpH = 4.81KJ/3.6C = 1.34 KJ/C
anonymous
  • anonymous
That looks less confusing but thats above what I know
anonymous
  • anonymous
Alright, great! Thank you.
anonymous
  • anonymous
No problem!

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