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YumYum247

  • one year ago

Someone please help me!!!

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  1. anonymous
    • one year ago
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    good luck :)

  2. YumYum247
    • one year ago
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    Thanks :)

  3. YumYum247
    • one year ago
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    49e) Determine the velocity of the elevator 12 sec after the passengers have entered the elevator.

  4. YumYum247
    • one year ago
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    @Abhisar

  5. Abhisar
    • one year ago
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    Ok, what's the question?

  6. YumYum247
    • one year ago
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    49e) Determine the velocity of the elevator 12 sec after the passengers have entered the elevator.

  7. Abhisar
    • one year ago
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    Have you calculated the net acceleration?

  8. YumYum247
    • one year ago
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    10.29m/sec^2 = Net Acceleration

  9. Abhisar
    • one year ago
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    You can use v=u+at now to find v after 12 seconds.

  10. YumYum247
    • one year ago
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    but i don't know my initial velocity!!

  11. YumYum247
    • one year ago
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    i was plannign on using Vf = Vi X a.t but i don't have the initial velo

  12. Abhisar
    • one year ago
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    Applied force - (Frictional force + Gravitational Force) = Net Force

  13. YumYum247
    • one year ago
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    ok?

  14. YumYum247
    • one year ago
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    what do i do with that?!?!?!? what will i get tho?!?!?!?

  15. Abhisar
    • one year ago
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    I think you have calculated the net accn wrong...

  16. YumYum247
    • one year ago
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    can you please take 2 seconds and go back and read 49b)

  17. YumYum247
    • one year ago
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    it's at the top.

  18. Abhisar
    • one year ago
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    Ok, let's see that part again. There are 3 forces acting on the elevator. Force due to the elevator cable upwards, force of friction downwards and gravitational force downwards. Right?

  19. YumYum247
    • one year ago
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    are you saying that i should have combined the frictional and gravitational forces?!?!? Applied force - ""(Frictional force + Gravitational Force)"" = Net Force

  20. YumYum247
    • one year ago
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    yes that;s right!

  21. Abhisar
    • one year ago
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    Yeah, that's what i am saying !!

  22. YumYum247
    • one year ago
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    but i didn't include the gravitational force for some reason idek. i though once an object overcome the force of gravity, the effects of gravity don't count.

  23. Abhisar
    • one year ago
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    No that's not true..

  24. YumYum247
    • one year ago
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    ok please help me here for a sec. If an object is travelling faster than 9.80m/sec^2 up, does the effects/ the gravitational force count?

  25. Abhisar
    • one year ago
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    Yes, gravity is always working. Suppose a body is of mass 1 Kg is travelling with an acceleration 10m/s^2 then it means that force acting on it is 20 N. 10 N is used in neutralising the gravitational force and then other 10N for giving its acceleration.

  26. YumYum247
    • one year ago
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    because imagine if your inside an elevator which is going at 15m/sec^2, your initial mass is 50Kg, would you not feel heavier due to the sheer upward force the evelator is pressing you with?????

  27. Abhisar
    • one year ago
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    Read this http://hyperphysics.phy-astr.gsu.edu/hbase/elev.html

  28. YumYum247
    • one year ago
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    ok...so once i have my net acceleration how do i determine the velocity of the elevator? Please just leave the formula. and i'll do the rest :)

  29. Abhisar
    • one year ago
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    v=u+at V is your final velocity, u is your initial velocity which is 0 in this case, a and t are acceleration and time.

  30. YumYum247
    • one year ago
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    ok Thanks and I Love you!!! Muuuuuha :"D GOD BLESS YOU DEAR. Long Live!!

  31. Abhisar
    • one year ago
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    o_O You're welcome..

  32. YumYum247
    • one year ago
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    :"D

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