hpfan101
  • hpfan101
\[\lim_{x \rightarrow \infty} \sqrt{9x^2+x}-3x\]
Calculus1
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
gimmick is to multiply by \[\frac{\sqrt{9x^2+x}+3x}{\sqrt{9x^2+x}+3x}\]
hpfan101
  • hpfan101
When I multiplied by the conjugate I got: \[\frac{ 9x^2+x-9x }{ \sqrt{9x^2+x}+3x }\]
hpfan101
  • hpfan101
Oh the denominator is supposed to be -x not +x

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hpfan101
  • hpfan101
Actually nevermind, it's +x.
anonymous
  • anonymous
\(-9x^{\color{red}2}\) in the numerator's second term
hpfan101
  • hpfan101
Oh ok.
hpfan101
  • hpfan101
Alright, I now know how to solve the question from there. Thank you guys!

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