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  1. Nnesha
    • one year ago
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    |dw:1443148206372:dw| now u can use the parabola equation to find p

  2. anonymous
    • one year ago
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    ok, thanks

  3. Nnesha
    • one year ago
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    use the standard equation http://colalg.math.csusb.edu/~devel/precalcdemo/conics/src/parabola.html

  4. Nnesha
    • one year ago
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    np let me know if u have a question

  5. anonymous
    • one year ago
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    unable find focus ?

  6. anonymous
    • one year ago
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    I did use standard but the answer not work out

  7. Nnesha
    • one year ago
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    alright show ur work what did yo uget ?

  8. Nnesha
    • one year ago
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    if the parabola opens up then we should use x^2=4py ^thats in the link

  9. anonymous
    • one year ago
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    PD= PF F=( 0,y) P=(6,4) D=(6,y) ( 6-0)^2+(4-y)^2 = (6-6)^2+(4-y)^2 36=o

  10. anonymous
    • one year ago
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    formula: y=1/4P*X^2

  11. anonymous
    • one year ago
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    \[y=\frac{ 1 }{4P }X ^{2}\]

  12. anonymous
    • one year ago
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    How I find P?

  13. Nnesha
    • one year ago
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    this might be a stupid question what's PD and PF in this question ?

  14. Nnesha
    • one year ago
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    ohh ye that's the same equation as x^2 =4py if we multiply both sides by 4p

  15. Nnesha
    • one year ago
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    use the order pair (6,4) where x =6 and y=4 plugin

  16. anonymous
    • one year ago
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    F is the point of focus P is the point pass through parabola D is the point Directrix The not of Algebra 2 said

  17. Nnesha
    • one year ago
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    Cool.

  18. anonymous
    • one year ago
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    you can look the link you send what is P?

  19. Nnesha
    • one year ago
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    my question was what's PF and PD `in this question`

  20. Nnesha
    • one year ago
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    i didn't read all of it in that link but according my notes p =distance

  21. Nnesha
    • one year ago
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    to*

  22. Nnesha
    • one year ago
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    \[\huge\rm (6)^2=4p(4)\] now u can solve for p

  23. Nnesha
    • one year ago
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    hope that helpd

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