## anonymous one year ago http://s1142.photobucket.com/user/nancylam67/media/Screen%20Shot%202015-09-24%20at%206.36.24%20PM.png.html I need help number 9 only , thanks

1. Nnesha

|dw:1443148206372:dw| now u can use the parabola equation to find p

2. anonymous

ok, thanks

3. Nnesha

use the standard equation http://colalg.math.csusb.edu/~devel/precalcdemo/conics/src/parabola.html

4. Nnesha

np let me know if u have a question

5. anonymous

unable find focus ?

6. anonymous

I did use standard but the answer not work out

7. Nnesha

alright show ur work what did yo uget ?

8. Nnesha

if the parabola opens up then we should use x^2=4py ^thats in the link

9. anonymous

PD= PF F=( 0,y) P=(6,4) D=(6,y) ( 6-0)^2+(4-y)^2 = (6-6)^2+(4-y)^2 36=o

10. anonymous

formula: y=1/4P*X^2

11. anonymous

$y=\frac{ 1 }{4P }X ^{2}$

12. anonymous

How I find P?

13. Nnesha

this might be a stupid question what's PD and PF in this question ?

14. Nnesha

ohh ye that's the same equation as x^2 =4py if we multiply both sides by 4p

15. Nnesha

use the order pair (6,4) where x =6 and y=4 plugin

16. anonymous

F is the point of focus P is the point pass through parabola D is the point Directrix The not of Algebra 2 said

17. Nnesha

Cool.

18. anonymous

you can look the link you send what is P?

19. Nnesha

my question was what's PF and PD in this question

20. Nnesha

i didn't read all of it in that link but according my notes p =distance

21. Nnesha

to*

22. Nnesha

$\huge\rm (6)^2=4p(4)$ now u can solve for p

23. Nnesha

hope that helpd