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anonymous
 one year ago
@hwyl
anonymous
 one year ago
@hwyl

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Domain and range looking at graphs

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0There is nothing to go on v,v I don't know how to do it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Omg satellite don't make fun of me ;;

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh okay we have domain codomain range do you know each of those?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i was laughing at @hwyl

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I know that domain is the xvalues and range is the y. I can do it based off of coordinates but I can't do it based off of graphs

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh okay that's fine create a graph for me do not label

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1443148507651:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It's mostly the unlabled infinity graphs I have issues with

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0just when I said do not label _

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0let us do an example based off your book

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1443148694480:dw Start with an easy cubic

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0we're going to use the most basic cube function \(f(x) = x^3 \)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so what is the domain of the function?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[(\infty, \infty)\] ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0this is when you try to think about the pretty setbuilder notation or that

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can x be any number?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0think hard, what condition that it won't work

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I feel really stupid for not knowing =.=

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0we have Real numbers etc etc

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Imaginary numbers? So like i and stuff I guess

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1443149075246:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yeah, the solid lines like that I'm okay with. It's stuff that I don't see an end to like parabolas and cubic graphs etc

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so pretty much any real number is valid

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1443149216613:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@satellite73 , R=all real numbers?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0This is where I start getting lost haha

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1443149291544:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0since you were talking about infinities, let us try something periodic with infinity

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0just pardon my drawing

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it's basically a graph of \(tan(x) \)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0suppose the domain, codomain and range

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0went too happy with the vertical lines

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1443149631927:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1443149780293:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0let us see what the domain, range and period

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I don't need to know period or codomain. It's alg2 level rn

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh so what is the domain and range?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0domain [pi/2, pi/2] range (inf, inf)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay now think carefully does the x really cross or touch +/ pi/2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so you can't really say \( \pm\pi/2 \)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0maybe we can suppose that it is \(x \neq \pm \pi/2\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0v,v I won't have super complex domains and ranges on this test though

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh okay then let us make it easier how about sin x draw the graph and indicate the domain and range

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1443150342371:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0make it a little smaller

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Please tell me thats a sin graph...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ur jelly of my drawing skills

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1443150458901:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1443150441508:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1443150577160:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0indicate your domain and range

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Domain [0, inf) Range [1, 1]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1443150722246:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes, because there is no constraint in the value of x provided that we use Real number

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@iambatman we need to do polarization later

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0always from left to right or least to most so negative to positive

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you pretty much get it already

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yeah I guess so. I just have to think about them. I can do linear because I can physically see, stuff with infinity is a bit more abstract

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1443151574827:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what is your domain and what is your range?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0For some reason this puzzles me ;;

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0alright start with range

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That's the part that's confusing me....... this is stupid v,v lol

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1443151869375:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can my range go lower than a?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so there you go, you start with that value range:[1, inf)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh I guess that makes sense. I got the 1 but I wasn't sure about the second coordinate

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I mean range:[a, inf)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0pellet, I was going to ask you about the one with the detailed function

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0instead of an actual number, I assigned a

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but they are the same dw:1443152138070:dwdw:1443152147095:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you said earlier that domain is x and range is y dw:1443152218860:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0these are specific domains x, which gives you a range dw:1443152497889:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but see, no matter what values you have for x, your y can only go up from 1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Hey I appreciate you helping me :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that's why our range starts from 1 to infinity

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that is because how the function is set up, constrained by the constant k dw:1443152666861:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do you want me to get a few sample problems from a book?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Nah, I think I've got it. And even if I get like the 2 problems with domain and range wrong I know the rest of the stuff lol. I think I'll be fine. Thank you for helping me :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay that's from a graph, how about from a function or equation?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0And I'm starting to not process stuff lol. I think I'm good for now

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\(\large f(x) = \frac{1}{x^24} \)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can you write your domain in setbuilder notation?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Mehhh lemme look at some examples and come back to this

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0wowwwww lol alright, I need to grab something to eat

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I can't remember how to do it lol

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh, you just need to remember the definition of a function

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The ycoordinates can be the same, there just can't be more than one xcoordinate

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so your domain basically anything that the denominator will not be zero

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So it can't be 2 or 2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\(x^2 + 4 = 0 \) solve for x

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0correct, so all real except for those two

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0How do I do that with notation?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(inf, 2] u [2, 2] u [2, inf)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\(xx~ \epsilon~ \mathbb{R}, x \neq \pm 2 \)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I think my teacher wants me to use that stupid u thing

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it is time for you to master it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0between precal and cal, there's usually a program that helps you hone skills on logic and these notations

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0inquire about it in your math department it will help a lot

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay let us attempt to drive this home
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