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anonymous
 one year ago
A mixture of He and Ne at a total pressure of 0.95 atm is found to contain 0.32 mol of He and 0.56 mol of Ne. The partial pressure of Ne is ___ atm
anonymous
 one year ago
A mixture of He and Ne at a total pressure of 0.95 atm is found to contain 0.32 mol of He and 0.56 mol of Ne. The partial pressure of Ne is ___ atm

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Rushwr
 one year ago
Best ResponseYou've already chosen the best response.1\[P _{total} = P _{He} + P _{Ne}\] Partial pressure of a gas = molar fraction x total pressure

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0How do i find the molar fraction?

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.1Molar fraction = no. of moles of one component divided by the total no. of moles of all the compounds in the mixture

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.1The molar fraction of Ne would be \[\frac{ 0.56mol }{ (0.56 + 0.32)mol }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Awesome! so then i take that times 0.95?
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