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anonymous

  • one year ago

A mixture of He and Ne at a total pressure of 0.95 atm is found to contain 0.32 mol of He and 0.56 mol of Ne. The partial pressure of Ne is ___ atm

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  1. Rushwr
    • one year ago
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    \[P _{total} = P _{He} + P _{Ne}\] Partial pressure of a gas = molar fraction x total pressure

  2. anonymous
    • one year ago
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    How do i find the molar fraction?

  3. Rushwr
    • one year ago
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    Molar fraction = no. of moles of one component divided by the total no. of moles of all the compounds in the mixture

  4. Rushwr
    • one year ago
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    The molar fraction of Ne would be \[\frac{ 0.56mol }{ (0.56 + 0.32)mol }\]

  5. anonymous
    • one year ago
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    Awesome! so then i take that times 0.95?

  6. Rushwr
    • one year ago
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    yep

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