anonymous
  • anonymous
find any vertical asymptotes of the function limit of 1 divided by the quantity x minus 8 as x approaches 8 from the left
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
https://i.gyazo.com/600783c4843f253829c56f7ccc1a8a91.png
anonymous
  • anonymous
\[f(x)=\frac{1}{x-8}\]?
anonymous
  • anonymous
yea.

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anonymous
  • anonymous
you know what it looks like?
anonymous
  • anonymous
not exactly
anonymous
  • anonymous
has a vertical asymptote at \(x=8\) for sure
anonymous
  • anonymous
did you graph these in some pre-calc class?
anonymous
  • anonymous
this is for my final assignment for my online class
anonymous
  • anonymous
actually we can cheat easily, do it without knowing the graph
anonymous
  • anonymous
oh well if it is on line lets cheat like crazy
anonymous
  • anonymous
http://www.wolframalpha.com/input/?i=1%2F%28x-8%29
anonymous
  • anonymous
you and i would become good friends lol
anonymous
  • anonymous
you can see that as \(x\to 8^-\) it goes to \(-\infty\)
anonymous
  • anonymous
you can see that from the picture right?
anonymous
  • anonymous
yea
anonymous
  • anonymous
ok my motto "cheating is learning"
anonymous
  • anonymous
awesome. that is now my new motto
anonymous
  • anonymous
all rights reserved
anonymous
  • anonymous
wait so is x=8 the only one?
anonymous
  • anonymous
yes of course
anonymous
  • anonymous
only place where the denominator would be zero
anonymous
  • anonymous
ok thank you so much
anonymous
  • anonymous
yw
anonymous
  • anonymous
and is it ok if you can help me with one last question
anonymous
  • anonymous
ok one last question
anonymous
  • anonymous
Find the fifth roots of 243(cos 240° + i sin 240°)
anonymous
  • anonymous
lord i thought it as going to be a short one
anonymous
  • anonymous
ok first the fifth root of 243 is 3 i think
anonymous
  • anonymous
lol sorry.
anonymous
  • anonymous
then divide \(240\) by \(5\)
anonymous
  • anonymous
i get 48
anonymous
  • anonymous
that would be 48
anonymous
  • anonymous
yea
anonymous
  • anonymous
so one answer is \[ 3(\cos (48°) + i \sin (48°))\]
anonymous
  • anonymous
next we add 360 to 240 and divide by 5 again
anonymous
  • anonymous
ok so it would be 120
anonymous
  • anonymous
\[360+240=600,600\div 5=120\] right
anonymous
  • anonymous
so 2nd answer is \[3(\cos (120°) + i \sin (120°))\]
anonymous
  • anonymous
lather, rinse, repeat
anonymous
  • anonymous
alright. so once again i add 360 and divide by 5?
anonymous
  • anonymous
\[600+360=960, 960\div 5=192\]
anonymous
  • anonymous
3(cos(192°)+isin(192°))
anonymous
  • anonymous
third answer is \[3(\cos (192°) + i \sin (192°))\] you are too fast for me
anonymous
  • anonymous
haha sorry
anonymous
  • anonymous
no that is good, you get the picture, even though evidently you will never use this again
anonymous
  • anonymous
i will let you finish the last two \[960+360\] etc
anonymous
  • anonymous
ok thanks so much for the help. thats everything i needed help with
anonymous
  • anonymous
you are welcome, hope you pass

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