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anonymous

  • one year ago

find any vertical asymptotes of the function limit of 1 divided by the quantity x minus 8 as x approaches 8 from the left

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  1. anonymous
    • one year ago
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    https://i.gyazo.com/600783c4843f253829c56f7ccc1a8a91.png

  2. anonymous
    • one year ago
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    \[f(x)=\frac{1}{x-8}\]?

  3. anonymous
    • one year ago
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    yea.

  4. anonymous
    • one year ago
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    you know what it looks like?

  5. anonymous
    • one year ago
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    not exactly

  6. anonymous
    • one year ago
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    has a vertical asymptote at \(x=8\) for sure

  7. anonymous
    • one year ago
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    did you graph these in some pre-calc class?

  8. anonymous
    • one year ago
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    this is for my final assignment for my online class

  9. anonymous
    • one year ago
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    actually we can cheat easily, do it without knowing the graph

  10. anonymous
    • one year ago
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    oh well if it is on line lets cheat like crazy

  11. anonymous
    • one year ago
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    http://www.wolframalpha.com/input/?i=1%2F%28x-8%29

  12. anonymous
    • one year ago
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    you and i would become good friends lol

  13. anonymous
    • one year ago
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    you can see that as \(x\to 8^-\) it goes to \(-\infty\)

  14. anonymous
    • one year ago
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    you can see that from the picture right?

  15. anonymous
    • one year ago
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    yea

  16. anonymous
    • one year ago
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    ok my motto "cheating is learning"

  17. anonymous
    • one year ago
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    awesome. that is now my new motto

  18. anonymous
    • one year ago
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    all rights reserved

  19. anonymous
    • one year ago
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    wait so is x=8 the only one?

  20. anonymous
    • one year ago
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    yes of course

  21. anonymous
    • one year ago
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    only place where the denominator would be zero

  22. anonymous
    • one year ago
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    ok thank you so much

  23. anonymous
    • one year ago
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    yw

  24. anonymous
    • one year ago
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    and is it ok if you can help me with one last question

  25. anonymous
    • one year ago
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    ok one last question

  26. anonymous
    • one year ago
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    Find the fifth roots of 243(cos 240° + i sin 240°)

  27. anonymous
    • one year ago
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    lord i thought it as going to be a short one

  28. anonymous
    • one year ago
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    ok first the fifth root of 243 is 3 i think

  29. anonymous
    • one year ago
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    lol sorry.

  30. anonymous
    • one year ago
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    then divide \(240\) by \(5\)

  31. anonymous
    • one year ago
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    i get 48

  32. anonymous
    • one year ago
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    that would be 48

  33. anonymous
    • one year ago
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    yea

  34. anonymous
    • one year ago
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    so one answer is \[ 3(\cos (48°) + i \sin (48°))\]

  35. anonymous
    • one year ago
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    next we add 360 to 240 and divide by 5 again

  36. anonymous
    • one year ago
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    ok so it would be 120

  37. anonymous
    • one year ago
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    \[360+240=600,600\div 5=120\] right

  38. anonymous
    • one year ago
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    so 2nd answer is \[3(\cos (120°) + i \sin (120°))\]

  39. anonymous
    • one year ago
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    lather, rinse, repeat

  40. anonymous
    • one year ago
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    alright. so once again i add 360 and divide by 5?

  41. anonymous
    • one year ago
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    \[600+360=960, 960\div 5=192\]

  42. anonymous
    • one year ago
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    3(cos(192°)+isin(192°))

  43. anonymous
    • one year ago
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    third answer is \[3(\cos (192°) + i \sin (192°))\] you are too fast for me

  44. anonymous
    • one year ago
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    haha sorry

  45. anonymous
    • one year ago
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    no that is good, you get the picture, even though evidently you will never use this again

  46. anonymous
    • one year ago
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    i will let you finish the last two \[960+360\] etc

  47. anonymous
    • one year ago
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    ok thanks so much for the help. thats everything i needed help with

  48. anonymous
    • one year ago
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    you are welcome, hope you pass

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