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anonymous
 one year ago
Which functions are correct?
f(x) = 24x g(x) = 2x
Choose exactly two answers that are correct.
anonymous
 one year ago
Which functions are correct? f(x) = 24x g(x) = 2x Choose exactly two answers that are correct.

This Question is Closed

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1\[\large\rm f(x)=2^{4x},\qquad\qquad g(x)=2^x\]So then,\[\large\rm (fg)(x)=2^{4x}\cdot 2^x\]As a reminder, here is our relevant exponential rule:\[\large\rm \color{orangered}{a^x\cdot a^y=a^{x+y}}\]It tells us that when we multiply things that have the same base, we add the exponents.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1So what do you think? :o

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1So these are your two options:\[\large\rm 2^{4x}\cdot2^{x}=2^{4x+x}\]\[\large\rm 2^{4x}\cdot2^{x}=2^{4x\cdot x}\] Based on the rule I posted, which one seems correct?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the first one i guess

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1Good. And our division rule tells us to `subtract` the exponents.\[\large\rm \frac{f}{g}=\frac{2^{4x}}{2^x}=2^{4xx}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but why is it asking for 2 right answers?

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1Because we chose one correct answer for \(\large\rm (fg)(x)\), multiplication of these functions. We also need to chose one correct answer for \(\large\rm \left(\frac{f}{g}\right)(x)\), division of these functions.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what you think about A snd C?
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