shelby1290
  • shelby1290
Describe the steps needed to graph each of the following functions: a) f(x)=-x^2 + 34 b) f(x) =-5.5(x-6)^2+11 c) f(x)=1/10x^2+16 d) f(x) = -(x+18)^2+3
Mathematics
katieb
  • katieb
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hwyl
  • hwyl
they're all quadratic, correct?
shelby1290
  • shelby1290
The steps are supposed to be described in words, i believe.
hwyl
  • hwyl
so what do you know about quadratic functions?

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hwyl
  • hwyl
dot dot dot
hwyl
  • hwyl
http://jwilson.coe.uga.edu/emt668/EMAT6680.Folders/Barron/unit/Lesson%206/6.html
shelby1290
  • shelby1290
@hwyl so what do i write down?
hwyl
  • hwyl
read the contents of that website
DanJS
  • DanJS
depends on what kind of resolution or general shape you need
DanJS
  • DanJS
they are all quadratic, you can put them in y = ax^2 + bx + c form
DanJS
  • DanJS
most important values to graph, Vertex x-intercept if any y-intercepts if any
shelby1290
  • shelby1290
@DanJS , @hwyl i don't think i can say the same answer for all of them though
DanJS
  • DanJS
start with one of them, and explain and show how to get a basic graph
DanJS
  • DanJS
f(x) = -x^2 + 34 vertex--- x = -b/(2*a) = -0/-2 = 0 y=f(0) = 34 Vertex is at (x,y) = (0,34)
shelby1290
  • shelby1290
okay so like for example with part a) Find the vertex, create a table of values, and graph them?
DanJS
  • DanJS
the sin on the coefficient of the squarred term is negative, and tells you the parabola opens down...there will be x-intercepts x-intercepts are where y=0,, solve y = 0 = -x^2 + 34 plot the points (x,0)
shelby1290
  • shelby1290
It's just that i feel like the same steps are followed for the every question. So, i don't understand how you're supposed to find the steps for each one to differentiate in words
DanJS
  • DanJS
yeah, i would find the vertex first, then find the x and y axis intercepts if they exist
DanJS
  • DanJS
you can use numbers to, just explain what you are doing, and show the graph of each point you find
DanJS
  • DanJS
You can list the values in a table if you want, but not really needed
DanJS
  • DanJS
|dw:1443156593616:dw|
DanJS
  • DanJS
You can draw all that from just finding the vertex (0,34)
DanJS
  • DanJS
and knowing that the negative on the x^2 term means it opens down
DanJS
  • DanJS
then find the values where the function crosses the x axis +a and -a points (+a , 0) and (-a , 0) Those are the x intercepts found by solving y = f(x) = 0 = -x^2 + 34
DanJS
  • DanJS
that is all i would do, done
shelby1290
  • shelby1290
|dw:1443156876046:dw|
shelby1290
  • shelby1290
That's how the question is set up on my paper. ^^^ The question in its function notation with two lines underneath
DanJS
  • DanJS
|dw:1443156913742:dw|
shelby1290
  • shelby1290
every question is set up like that so there's no room to graph or anything like that
DanJS
  • DanJS
ok, just explaine however you need to how you would make a graph of that function
DanJS
  • DanJS
if it is blank paper, i would assume you can draw and show equations as long as you back it up with a worded explination
DanJS
  • DanJS
" the function is this, ----, this is how you find the vertex point, ----, this is how you determine the direction of the parabola, this is how you find the axis intercepts if they exist for the function "
DanJS
  • DanJS
goodluck
shelby1290
  • shelby1290
@DanJS ahhh okay that makes more sense now. Thank you!
DanJS
  • DanJS
if you want more detail you can pick any x value and solve for the corresponding y value, and add as many random points you want and build a table
DanJS
  • DanJS
welcome, i think they just want the important points, so you can get a basic graph

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