Describe the steps needed to graph each of the following functions:
a) f(x)=-x^2 + 34
b) f(x) =-5.5(x-6)^2+11
c) f(x)=1/10x^2+16
d) f(x) = -(x+18)^2+3

- shelby1290

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- hwyl

they're all quadratic, correct?

- shelby1290

The steps are supposed to be described in words, i believe.

- hwyl

so what do you know about quadratic functions?

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## More answers

- hwyl

dot dot dot

- hwyl

http://jwilson.coe.uga.edu/emt668/EMAT6680.Folders/Barron/unit/Lesson%206/6.html

- shelby1290

@hwyl so what do i write down?

- hwyl

read the contents of that website

- DanJS

depends on what kind of resolution or general shape you need

- DanJS

they are all quadratic, you can put them in y = ax^2 + bx + c form

- DanJS

most important values to graph,
Vertex
x-intercept if any
y-intercepts if any

- shelby1290

@DanJS , @hwyl i don't think i can say the same answer for all of them though

- DanJS

start with one of them, and explain and show how to get a basic graph

- DanJS

f(x) = -x^2 + 34
vertex--- x = -b/(2*a) = -0/-2 = 0
y=f(0) = 34
Vertex is at (x,y) = (0,34)

- shelby1290

okay so like for example with part a)
Find the vertex, create a table of values, and graph them?

- DanJS

the sin on the coefficient of the squarred term is negative, and tells you the parabola opens down...there will be x-intercepts
x-intercepts are where y=0,, solve
y = 0 = -x^2 + 34
plot the points (x,0)

- shelby1290

It's just that i feel like the same steps are followed for the every question. So, i don't understand how you're supposed to find the steps for each one to differentiate in words

- DanJS

yeah, i would find the vertex first, then find the x and y axis intercepts if they exist

- DanJS

you can use numbers to, just explain what you are doing, and show the graph of each point you find

- DanJS

You can list the values in a table if you want, but not really needed

- DanJS

|dw:1443156593616:dw|

- DanJS

You can draw all that from just finding the vertex (0,34)

- DanJS

and knowing that the negative on the x^2 term means it opens down

- DanJS

then find the values where the function crosses the x axis +a and -a
points (+a , 0) and (-a , 0)
Those are the x intercepts found by solving y = f(x) = 0 = -x^2 + 34

- DanJS

that is all i would do, done

- shelby1290

|dw:1443156876046:dw|

- shelby1290

That's how the question is set up on my paper. ^^^
The question in its function notation with two lines underneath

- DanJS

|dw:1443156913742:dw|

- shelby1290

every question is set up like that so there's no room to graph or anything like that

- DanJS

ok, just explaine however you need to how you would make a graph of that function

- DanJS

if it is blank paper, i would assume you can draw and show equations as long as you back it up with a worded explination

- DanJS

" the function is this, ----, this is how you find the vertex point, ----, this is how you determine the direction of the parabola, this is how you find the axis intercepts if they exist for the function "

- DanJS

goodluck

- shelby1290

@DanJS ahhh okay that makes more sense now. Thank you!

- DanJS

if you want more detail you can pick any x value and solve for the corresponding y value, and add as many random points you want and build a table

- DanJS

welcome, i think they just want the important points, so you can get a basic graph

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