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the first one you can maybe think of it as intersection points for the line x + 3 and the parabola (x-5)^2
or you can graph the parabola, and show where it crosses the x axis
ax^2+bx+c = 0
7) goes to x^2 -11x +22 =0 ,
im allowed on use the sight https://www.desmos.com/calculator to graph it will you help me so i know what to type in each box im sorry im horrible at math lol
graph that parabola y = f(x) and show the x values where y = f(x) = 0
k, for 7) graph y=x^2-11x+22 show the x values when y is zero (x-axis) those are the solutions
OR Graph y=x+3 and y = (x-5)^2 and they should cross two times and have intersection points, the x values are the solutions
okay i graphed 7 thank you!
so how would i do numbers 8 and 9 now? im just confused on how to rearrange them like you did
show where x^4 - x + 1 crosses the x axis
y = x^4 - x + 1 if it even does
another approach do a table with x values (common -3 to 3) calculate the corresponding y value plot the points "see" the intersection
i think that is what they want, as @triciaal says,, just show how many times y = f(x) froses the x axis, number of roots, just "see" it
the point to know the general shape of each of those degrees
okay i graphed number 8 its correct thank you
what would number 7 be?
okay perfect mine looks like that too
but number 8 was no solution so what would be 7?
graph x^2 - 11x + 22
see where it crosses the x axis, might need the quadratic formula for a specific values
okay got it thank you! would that mean complex solution
what would number 9 be?
i just need the equation so i can graph it and to determine the number of solutions for 7 8 and 9
for each of the above equations you have the y's equal to graph "split" into the 2 y's and graph for example, number 9 given x^3 = 5 - x means graph 1 y = x^3 and graph 2 y = 5- x when they intersect means the x values that satisfies both equations with that y value
okay thank you so much
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