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or you can graph the parabola, and show where it crosses the x axis

ax^2+bx+c = 0

7) goes to x^2 -11x +22 =0 ,

graph that parabola y = f(x) and show the x values where y = f(x) = 0

k, for
7) graph y=x^2-11x+22
show the x values when y is zero (x-axis) those are the solutions

okay i graphed 7 thank you!

so how would i do numbers 8 and 9 now? im just confused on how to rearrange them like you did

show where x^4 - x + 1 crosses the x axis

y = x^4 - x + 1
if it even does

the point to know the general shape of each of those degrees

okay i graphed number 8 its correct thank you

no solution

what would number 7 be?

|dw:1443159176123:dw|

okay perfect mine looks like that too

but number 8 was no solution so what would be 7?

|dw:1443159283029:dw|

graph x^2 - 11x + 22

see where it crosses the x axis, might need the quadratic formula for a specific values

okay got it thank you! would that mean complex solution

|dw:1443159406311:dw|

|dw:1443159578443:dw|

what would number 9 be?

i just need the equation so i can graph it and to determine the number of solutions for 7 8 and 9

okay thank you so much