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anonymous

  • one year ago

Factor completely: 3a^2-20ab+12b^2

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  1. anonymous
    • one year ago
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    \[3a ^{2}-20ab+12b ^{2}\]

  2. jim_thompson5910
    • one year ago
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    multiply the first and last coefficients 3*12 = 36

  3. jim_thompson5910
    • one year ago
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    find two numbers that multiply to 36 and that add to -20

  4. anonymous
    • one year ago
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    18 and 2

  5. jim_thompson5910
    • one year ago
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    actually -18 and -2 -18 times -2 = +36 -18 plus -2 = -20

  6. anonymous
    • one year ago
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    What is the next step? I'm confused on the different variables.

  7. jim_thompson5910
    • one year ago
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    \[\Large 3a ^{2}\color{red}{-20ab}+12b ^{2}\] \[\Large 3a ^{2}\color{red}{-18ab}\color{red}{-2ab}+12b ^{2}\] now factor by grouping

  8. anonymous
    • one year ago
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    (3a^2-18ab) (-2ab+12b^2)

  9. jim_thompson5910
    • one year ago
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    don't forget the plus in between (3a^2-18ab) + (-2ab+12b^2)

  10. jim_thompson5910
    • one year ago
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    now factor each group

  11. anonymous
    • one year ago
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    3a(a-6b) 2b(-1a+6b)

  12. anonymous
    • one year ago
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    did i do it wrong? i feel like the 2nd group is incorrect.

  13. jim_thompson5910
    • one year ago
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    (3a^2-18ab) + (-2ab+12b^2) 3a(a-6b) + (-2ab+12b^2) 3a(a-6b) -2b(a - 6b) there's one more step

  14. anonymous
    • one year ago
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    What would the next step be?

  15. anonymous
    • one year ago
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    oh i know it :D

  16. anonymous
    • one year ago
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    (3a-2b) (a-6b)

  17. jim_thompson5910
    • one year ago
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    good

  18. anonymous
    • one year ago
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    Thanks for the help @jim_thompson5910 :)

  19. jim_thompson5910
    • one year ago
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    no problem

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