## moonlight93 one year ago I have the answers, but I need to know how to get it. I need help. In a sample distribution, x=56 corresponds to z= 1.00 and x=47 corresponds to z = -0.50. find the mean and standard deviation for the sample. ____________ Answer: mean= 50 standard deviation= 6

1. marco26

I wonder if you still need the solution, but here it is: $z=\frac{ (x-mean) }{ SD }$ where SD is the standard deviation. when x=56 and z=1: $1=\frac{ 56-mean }{ SD }$ $SD= 56- mean$ --> eq. 1 when x=47, z=-0.5: $-0.5=\frac{ 47-mean }{ SD }$ but we have an equation for SD previously, substitute it $-0.5=\frac{ 47-mean}{ 56-mean }$ Solving for mean, you will get 50. Substitute 50 to get SD: $SD=56-mean=56-50=6$

2. moonlight93

Yes I do, I'm studying for an upcoming exam :) Thank you! @macro26