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moonlight93
 one year ago
I have the answers, but I need to know how to get it. I need help.
In a sample distribution, x=56 corresponds to z= 1.00 and x=47 corresponds to z = 0.50.
find the mean and standard deviation for the sample.
____________
Answer:
mean= 50
standard deviation= 6
moonlight93
 one year ago
I have the answers, but I need to know how to get it. I need help. In a sample distribution, x=56 corresponds to z= 1.00 and x=47 corresponds to z = 0.50. find the mean and standard deviation for the sample. ____________ Answer: mean= 50 standard deviation= 6

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marco26
 one year ago
Best ResponseYou've already chosen the best response.1I wonder if you still need the solution, but here it is: \[z=\frac{ (xmean) }{ SD }\] where SD is the standard deviation. when x=56 and z=1: \[1=\frac{ 56mean }{ SD }\] \[SD= 56 mean \] > eq. 1 when x=47, z=0.5: \[0.5=\frac{ 47mean }{ SD }\] but we have an equation for SD previously, substitute it \[0.5=\frac{ 47mean}{ 56mean }\] Solving for mean, you will get 50. Substitute 50 to get SD: \[SD=56mean=5650=6\]

moonlight93
 one year ago
Best ResponseYou've already chosen the best response.0Yes I do, I'm studying for an upcoming exam :) Thank you! @macro26
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