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anonymous

  • one year ago

PLEASE HELP ME!!! Given the equation below, solve for y.

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  1. anonymous
    • one year ago
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    z-4=\[z-4\frac{ y ^{2}+8z-48}{ z-4 }\]

  2. anonymous
    • one year ago
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    @Jhannybean please help me

  3. anonymous
    • one year ago
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    @kohai please can you help me??

  4. DanJS
    • one year ago
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    you get anyqwhere?

  5. anonymous
    • one year ago
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    @DanJS please help me

  6. anonymous
    • one year ago
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    is it going to be y=z-4?

  7. DanJS
    • one year ago
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    you need to isolate y on one side and it will = something in terms of all the other stuff, x

  8. DanJS
    • one year ago
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    I would multiply both sides of the thing by (z-4) first

  9. anonymous
    • one year ago
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    y=z-8 is this the answer?

  10. DanJS
    • one year ago
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    should that be a +8y instead of the +8z you typed?

  11. anonymous
    • one year ago
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    its a multiple choice question is my answer right?

  12. DanJS
    • one year ago
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    |dw:1443160932457:dw|

  13. anonymous
    • one year ago
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    its 8z

  14. DanJS
    • one year ago
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    ok, just checking, that makes it easier, asking because a y would be a factorable numorator.

  15. DanJS
    • one year ago
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    multiply both sides by (z-4) (z - 4)*(z-4) = y^2 + 8z - 48

  16. DanJS
    • one year ago
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    expand z^2 - 8z + 16 = y^2 + 8z - 48

  17. anonymous
    • one year ago
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    \[y=\sqrt{z ^{2}+6z-40}\]

  18. DanJS
    • one year ago
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    move the 8z and the -48 to the other side... z^2 - 16z + 64 = y^2

  19. DanJS
    • one year ago
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    take the root of both sides, and you get two answers for y, the + and the - root of all that on the left

  20. DanJS
    • one year ago
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    \[y = \pm \sqrt{z^2-16z+64}\]

  21. DanJS
    • one year ago
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    looking closer, the stuff under the root is a perfect square, factors to (z-8)^2 so you get simplified y = z - 8 or y = -(z-8)

  22. anonymous
    • one year ago
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    so thats the answer? because i said y=z-8

  23. anonymous
    • one year ago
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    @DanJS

  24. DanJS
    • one year ago
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    sorry, back

  25. DanJS
    • one year ago
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    yeah if that is the only choice in the multiple choice , there is also the negative of that , and there is a restriction on the values of z, but not sur eif you need that

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