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anonymous

  • one year ago

the set of zeros of f(x)=^3=4x^2+4x is

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  1. sloppycanada
    • one year ago
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    I assume you mean - \[f(x)=x^3=4x^2+4x?\]

  2. anonymous
    • one year ago
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    yes @sloppycanada

  3. zzr0ck3r
    • one year ago
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    that makes no sense... Do you mean \[f(x) = x^3+4x^2+4x\]?

  4. sloppycanada
    • one year ago
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    I'm really hoping it is @zzr0ck3r

  5. zzr0ck3r
    • one year ago
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    :)

  6. sloppycanada
    • one year ago
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    If it's \[x^3+4x^2+4x\], I can do that. @cutegirl

  7. anonymous
    • one year ago
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    it is @sloppycanada

  8. zzr0ck3r
    • one year ago
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    factor a \(x\) out and tell me what you got

  9. anonymous
    • one year ago
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    ^3+4^2+4=8^5?

  10. anonymous
    • one year ago
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    @zzr0ck3r

  11. zzr0ck3r
    • one year ago
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    what does ^3 mean?

  12. zzr0ck3r
    • one year ago
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    where did the x's go?

  13. DanJS
    • one year ago
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    factor the common x term from each f(x) = (x)*(x^2+4x+4) The zeros are found when it crosses the x axis, or when y = f(x) = 0, solve for the x values

  14. anonymous
    • one year ago
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    so 0,2 ? @DanJS

  15. anonymous
    • one year ago
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    its really 0,-2

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spraguer (Moderator)
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