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anonymous

  • one year ago

how do i find t^-1 (x) if t(x) = x^2 - 6x +5

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  1. jennithemeani
    • one year ago
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    First you make t(x) y then switch the variables x and y and isolate y then make y t(x) again

  2. ParthKohli
    • one year ago
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    The problem with this function is that it is not one-to-one.

  3. anonymous
    • one year ago
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    yeah i got (x-1) (x-5) = y.... i need to make x the subject of the formula... i don't know how to do that

  4. LynFran
    • one year ago
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    let t(x)=y so y=x^2-6x+5 solve for x y-5+9=x^2-6x+9 y+4=(x-3)^2 sq.rt(y+4)=(x-3) sq.rt(y+4)+3=x now to find the inverse replace x with y ..and y with x so sq.rt(x+4)+3=y

  5. anonymous
    • one year ago
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    thank u

  6. LynFran
    • one year ago
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    welcome

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