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anonymous

  • one year ago

Given that x, 4, x+6 are consecutive terms of a geometric series, find: (a) the possible values of x So I got x=2 but part from trying every number to see I don't know of a method to find the possible values. I don't know how many values they want so if there is a method that shows all the possible values that would be better.

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  1. welshfella
    • one year ago
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    Geometric series so common ratio = second term / first = third / second so 4 / x = (x + 6) / 4 solve for x

  2. welshfella
    • one year ago
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    that rearranges to the quadrataic equation x^2 + 6x - 16 = 0

  3. welshfella
    • one year ago
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    can you solve that?

  4. welshfella
    • one year ago
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    x = 2 is one of the possible values

  5. welshfella
    • one year ago
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    you need to factor x^2 + 6x - 16 you want 2 numbers whose product is -16 and whose sum = + 6

  6. welshfella
    • one year ago
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    have you learned how to solve these type of equations?

  7. anonymous
    • one year ago
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    Yes I have done quadratics before. I will try that now quickly

  8. anonymous
    • one year ago
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    I got the right thing! Thank you very much!

  9. welshfella
    • one year ago
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    yw

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