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anonymous
 one year ago
university 1st year math question
anonymous
 one year ago
university 1st year math question

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@IrishBoy123 can u plz help me and also how to use owl bucks ?

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1start by finding a way to describe the volume of the trough with h as the variable. where h is the height above the base of the trough. width of the trough changes as h increases, the length is constant.

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1dw:1443176643865:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can u plz delete the question of the photo legally i am not allowed to post it anywhere its from our university and after this i was going to delete my attachment hope u dont mind

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1dw:1443176712781:dw

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1w = width does that w = 4 + h/4 make sense to you?

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1if so, what is the shaded area in terms of h? dw:1443177106816:dw

baru
 one year ago
Best ResponseYou've already chosen the best response.1the shape of the drain isn't mentioned...?

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1soz that drawing is the trough, a trapezoidal prism

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0its a tricky question

baru
 one year ago
Best ResponseYou've already chosen the best response.1soo... assuming the entire bottom surface is the drain?

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1no leave the drain alone for now!

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1the fudge factor k seems to deal with that

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1we just need a formula for the shaded area in terms of h. it is a trapezoidal prism so basic geometry

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i am going to post this question again with ask qualified help thing hope u dont mind

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1go for it, that's completely not a problem! and good luck to you!

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1you should probs close this one though....as there will be confusion:p

baru
 one year ago
Best ResponseYou've already chosen the best response.1anyway...for arguments sake... you would write volume(V) in terms of 'h' and solve the diff equation by of variables dV/dt= k*h^(1/2) right?

baru
 one year ago
Best ResponseYou've already chosen the best response.1*by separation of variables

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1no separation had we proceeded we would have got for the trough something like \(V = 10(4h + \frac{h^2}{8})\) [i think the length was 10, the pic's gone now] so \(\dot V = 10(4 + \frac{h}{4})\dot h\) and for the drain from \(v = \sqrt{2gh}\) we would have got \(\dot V = k \sqrt{2gh}\) [never got down to nailing the k but i think it would have been a proxy for the area of the drain] so \(10(4 + \frac{h}{4})\dot h = k \sqrt{2gh}\) that's why it is a plot,

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1@baru oh my bad, yes you can do \(\frac{10(4 + \frac{h}{4})}{\sqrt{2gh} } \, dh = k \, dt\) etc if you wanted an analytic solution but i recall they wanted a plot.

baru
 one year ago
Best ResponseYou've already chosen the best response.1yep... i don't remember the question specifics either. i was just look looking for the underlying idea :)

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1fluid flow and continuity. i'm sure you know that anyways:p
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