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anonymous
 one year ago
university 1st year math question.
anonymous
 one year ago
university 1st year math question.

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welshfella
 one year ago
Best ResponseYou've already chosen the best response.0i looked up torricelli's law and only found a formula for a cylindrical tank..

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i am finding it very difficult

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.6@ParthKohli try this

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1are you mathmath333?

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1I haven't studied fluids yet, but I looked at the Wikipedia page and it sorta makes sense.

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1This is what we're really looking at though. https://en.wikipedia.org/wiki/Torricelli%27s_law#Application_for_time_to_empty_the_container

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.6same here, it seems torcelli's law gives the speed of fluid of height \(h\), leaving tank from bottom : \[v = \sqrt{2gh}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0noo \[v=\sqrt{2gh}\]

ytrewqmiswi
 one year ago
Best ResponseYou've already chosen the best response.0What does that k represents?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i was thinking of an approach where i find A(h) and use integration

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1Is that the area of crosssection as a function of height? And are you sure this is the equation?\[A(h) \frac{dh}{dt} = k \sqrt{h}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes 100% because we havent used other v=sqrt2gh yet and my teacher wouldnt expect us to use that

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the only problem i am having is how to find A(h)

ytrewqmiswi
 one year ago
Best ResponseYou've already chosen the best response.0That wuld mean that the area of cross section varies with height will that make any sense?

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1But in your equation, \(\sqrt{2g}\) or \(g\) won't appear. We can find the area of the crosssection as a function of height.

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1If my eyes work, we're looking at a rectangular crosssection, right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and yes i wan to find the area as a function of height plz

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1Width increases in a linear manner from 4 to 5. At h = 0, it is 4 and at h = 4, it is 5. Thus in general it should be \(w(h) = h/4 + 4\). Meanwhile the length remains 10 so \(l(h) = 10\). Multiply...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ 10h }{ 8 }\]

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1noooo I didn't write h/8 h/4+4 means (1/4)*h + 4

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ 10(h+16) }{ 4 }\]

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.640> 50 A(y) = 40 + (y/4)*10 does that work ?

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1it only works because one of them remains constant can't do the same thing when both width and length increase which is why it's a good practice to do them separately

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.6yeah 10cm is fixed, only the other dimension is changing, so it is linear

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0just a question srry interpreting ur thought process how did u get width as (1/4) times h +4

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.6\[A(h)\frac{ dh }{ dt }=k \sqrt{h}\] plugin \(A(h)\), the de becomes \[(40+(\frac{h}{4})*10)\frac{ dh }{ dt }=k \sqrt{h}\]

ytrewqmiswi
 one year ago
Best ResponseYou've already chosen the best response.0the liquid escapes with a velocity =sqrt(2gh) which varies with the level of liquid. Hence, we have to use integral. Let y be the height of the liquid at an instant. This height changes by dy in time dt. Volume of water leaving out per secound=Ady.dt at the hole volume escaping per second is av=a[sqrt(2gy)] a[sqrt(2gy)] =Ady/dt >\[\int\limits_{H}^{0}\frac{ dy }{ \sqrt{y} } =\frac{ a \sqrt{2g} }{ A }\int\limits_{t}^{0}dt\] \[t=\frac{ A }{ a \sqrt{2g}}2\sqrt{H}\] a<<A? what did i do o.o

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.6maybe think of it in reverse : A(h) = 40 + (h/4)*10 plugin h=0, what do you get ? plugin h=4, what do you get ?

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1dw:1443179501695:dw

ytrewqmiswi
 one year ago
Best ResponseYou've already chosen the best response.0well...that thing can be used to find time tho..?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@ytrewqmiswi we cant use v=sqrt2gh because well i want the area as a function of h

ytrewqmiswi
 one year ago
Best ResponseYou've already chosen the best response.0A = cross sectional area of tank H=height till water is filled a=cross sectional area of hole

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1but didn't you assume A to be constant?

ytrewqmiswi
 one year ago
Best ResponseYou've already chosen the best response.0yes i took it constant

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1yes that solution matches ours so far

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0good because i am not sure about my final answer it doesnt make sense so i need to be assured

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1you shouldn't have any problem with integration

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but would love it if you solve it step by step plzzz

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it will make my life so easy

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.6you don't have teamviwer ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0again what is teamviewer?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do i have to buy it ?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.6no, it is a free screen sharing app

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0for the solution u an see i am stuck in the end

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ahm do i have to get it for this question

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1\[A(h) \frac{dh}{dt} = k\sqrt{h}\]We've got all messy differentials here. What we do is we take all the \(h\)terms to to one side and \(t\)terms to the other. Then integrate both sides with proper limits.

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{A(h)}{\sqrt h} dh=kdt\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ A(h) }{ \sqrt{h} } dh=k dt\]

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1Great. Now when \(t= 0\), \(h=4\). When \(t = t_0\), \(h = 0\). So you integrate both sides with those limits corresponding to each other.

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1OK, first put the value of \(A(h) \) in the equation and simplify. You don't have to type it out here. Keep doing that on paper. I'll guide you through each step.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0which A(h) value must i put?

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1The one we found out earlier?

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1We found the value of area of the crosssection in terms of height earlier, yes?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ 10(h+16) }{ 4 }\ /\sqrt{h} =kdt\]

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1Good. I know you're having trouble with typing everything out. So don't. Just keep doing it on paper alright?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no i need to show u , i can be writting jubrish

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.6//ahm do i have to get it for this question Absolutely not, but considering the fact that you already have a detailed solution which you don't understand it, the jibber jabber that I do here only confuses you more. If you have teamviewer, we could use voice also and engage more efficiently.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ h+16 }{ \sqrt{h}} dh =  \frac{ 2 }{ 10 } \times 0.03 dt\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@ganeshie8 i am on computer , will that work on this and how do i add uz

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.6Hey it is really not required, let try and finish it off here

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.6have you deleted the attachment ?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.6i couldn't find the solution above

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok u see i did the A(h) wrong then towards the end i thought when t=0 , h=3

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0my solution is wrong

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.6your A(h) looks fine to me

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and i dont seem to get what that refers to as 3 quarter filled

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so plz ignore the solution

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.6dude you're good, don't you see what you have is same as `A(h) = 40 + (h/4)*10`

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok so my solution makes sense all of it ok what about part c

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i just gave up on that

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and also i dunno how to go furthur from here

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.6so whats you final answer for part i

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i dunno what is h and t if i dunno t how am i suppose to find h

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.6Notice that the depth of water, h, is 0 when the tank is empty. so, for part iii, i think you simply plugin h=0 and solve \(t\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0is this what u saying?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.6I am asking you to simply replace \(h\) by \(0\) because, empty tank means that the depth of water is 0

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.6\[\frac{ 2 }{ 3 }\sqrt{h} (h+48)=0.012t+58.89\] \[0=0.012t+58.89\] solve \(t\) and you're done!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0just one question did uz consider the three quarter filled thing

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.6Oops! we missed that, my mistake, sorry, lets start over..

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok so part i is finding an expression we have done it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ur being sarcastic right

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.6we need to start over, our work for all parts is wrong because we assumed that the tank was full

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.6gimme some time, il type in the complete solution

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.0nice comforter I mean. Lol.

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.6Hey, it turns out our previous solution works out perfectly fine because we have worked it from bottom.

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.6No need to redo anything. we are good.

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.6@ParthKohli please double check if psble

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0srry last thing what about part b

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0as u said make h=0 and solve for T

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thnx guys cheers i got it

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.6deleted, let me know if you want me delete any other stuff

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no its ok thak uso much

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how can i manupilate above equation so the subject is h because thats what it is ultimately asking

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but the question is asking me to make h the subject

dan815
 one year ago
Best ResponseYou've already chosen the best response.1it says you can use wolfrad alpha so use that

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0noo i cant because its for graph only h vs t

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0when u read the question b (i) last line determine the depth of the milk at any instant after the drain has opened

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so we need to find expression where h is the subject and i did use wolfram alpha it didnt work there were always two h

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0did u understand i am after i want an expression where h = .....

dan815
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{ 2 }{ 3 }\sqrt{h} (h+48)=0.012t+58.89\]

dan815
 one year ago
Best ResponseYou've already chosen the best response.1you just specify in wolfram plot h vs t

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0look i am not talking about ii use wolfram alpha to obtain plot h verus t

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i am talking about question above (i)

dan815
 one year ago
Best ResponseYou've already chosen the best response.1oh i thought u are done that

dan815
 one year ago
Best ResponseYou've already chosen the best response.1do u want me to solve b(i)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how do i make h the subject

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how do i get rid of sqrt h

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so i have an expression like h =..... when i manipulate above eq

dan815
 one year ago
Best ResponseYou've already chosen the best response.1it's not going to be pretty

dan815
 one year ago
Best ResponseYou've already chosen the best response.1yes.. this 0.03 for k means nothing to me

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0k is just viscosity its a constant

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0see the solution u will realise

dan815
 one year ago
Best ResponseYou've already chosen the best response.1k im assuming is a function of the radius of the opening

dan815
 one year ago
Best ResponseYou've already chosen the best response.1yep see that equation u are using there is an application of the bernoullis principle, where that k in there would be some factor with the radius of the opening at the bottom accounted in for it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yea can u see any way where h is the subject

dan815
 one year ago
Best ResponseYou've already chosen the best response.1what do u mean h is the subject

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0h= depth in equation and t = time

dan815
 one year ago
Best ResponseYou've already chosen the best response.1what you have is good enough

dan815
 one year ago
Best ResponseYou've already chosen the best response.1i dont see where it says to make h the subject in your question

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok at 10 sec what would be the depth of tank can u give me answer for that by substituting 4 into the final eq

dan815
 one year ago
Best ResponseYou've already chosen the best response.1you gotta use nonlinear methods lol

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how would i use non linear method

dan815
 one year ago
Best ResponseYou've already chosen the best response.1just use matlab or something for now

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok thnx for ur help btw before u go mind deleting this whole question plz

dan815
 one year ago
Best ResponseYou've already chosen the best response.1you know as far as applications and solutions go solving for t=f(h) is good enough

dan815
 one year ago
Best ResponseYou've already chosen the best response.1as you can graph that, and rotating it returns h=f(t)

dan815
 one year ago
Best ResponseYou've already chosen the best response.1if you really must solve for h i can show u a way

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can u plz delete the expression above

dan815
 one year ago
Best ResponseYou've already chosen the best response.1it's not pretty yo uwill need to use complex numbers

dan815
 one year ago
Best ResponseYou've already chosen the best response.1and it might be too early for you right now in first year

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no dont i have solved its not pretttyyy
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