Will Fan and Medal!!! (√5-x) --------- = ????? (√x+5)

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Will Fan and Medal!!! (√5-x) --------- = ????? (√x+5)

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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no0 the answer choices are A. {x|x<5}
1 Attachment
^^ the attachment are the answer choices
@pooja195 we need you

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Other answers:

is your function: \(\dfrac{\sqrt{5-x}}{\sqrt{x+5}}\) ?
yes
\[\frac{\sqrt{5-x}\cdot \sqrt{x+5}}{\sqrt{x+5} \cdot \sqrt{x+5}}\]\[=\frac{\sqrt{25-x^2}}{x+5}\]
Im not too sure what you're looking for. Maybe you can specify your question. Are we looking for where x has a vertical asymptote?
idk i just have the questiona dn the answers
Here is the whole thing
1 Attachment
Hold on
  • phi
the domain are the "x" values you can use in your function and get a valid answer out. You can run into trouble if you divide by 0 (that is not allowed) or taking the square root of a negative number (that is not allowed, if we want real numbers for the answer) Normally, we would figure out what x values will cause trouble, and "not allow them" what is left over is the domain.
  • phi
First, look at the bottom \[ \sqrt{x+5} \] if that is 0, we would be dividing by 0 , and we don't allow that. notice if x=-5 we get sqr(0)= 0. we x=-5 is not allowed
  • phi
still looking at the bottom: \[ \sqrt{x+5} \] if x is less than -5, for example -6 we would have \[ \sqrt{-6+5}= \sqrt{-1} \] and we do not allow taking the square root of a negative number so we now know \( x\le -5\) is not allowed what is allowed is \( x \gt -5\) next, look at the top \[ \sqrt{5-x}\] if x is bigger than 5, we will get a negative number inside the square root, and that is not allowed. so x must be less than or equal to 5 we have \[ -5 \lt x \le 5\]
ok thanls so much @Nnesha
what ??? o.O
For helping me understand the problem thanks @Nnesha

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