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anonymous
 one year ago
Will Fan and Medal!!!
(√5x)
 = ?????
(√x+5)
anonymous
 one year ago
Will Fan and Medal!!! (√5x)  = ????? (√x+5)

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no0 the answer choices are A. {xx<5}

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0^^ the attachment are the answer choices

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@pooja195 we need you

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0is your function: \(\dfrac{\sqrt{5x}}{\sqrt{x+5}}\) ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{\sqrt{5x}\cdot \sqrt{x+5}}{\sqrt{x+5} \cdot \sqrt{x+5}}\]\[=\frac{\sqrt{25x^2}}{x+5}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Im not too sure what you're looking for. Maybe you can specify your question. Are we looking for where x has a vertical asymptote?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0idk i just have the questiona dn the answers

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Here is the whole thing

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Jhannybean @phi @Nnesha @ganeshie8 plz help

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@millsemily ok @ganeshie8 help?

phi
 one year ago
Best ResponseYou've already chosen the best response.0the domain are the "x" values you can use in your function and get a valid answer out. You can run into trouble if you divide by 0 (that is not allowed) or taking the square root of a negative number (that is not allowed, if we want real numbers for the answer) Normally, we would figure out what x values will cause trouble, and "not allow them" what is left over is the domain.

phi
 one year ago
Best ResponseYou've already chosen the best response.0First, look at the bottom \[ \sqrt{x+5} \] if that is 0, we would be dividing by 0 , and we don't allow that. notice if x=5 we get sqr(0)= 0. we x=5 is not allowed

phi
 one year ago
Best ResponseYou've already chosen the best response.0still looking at the bottom: \[ \sqrt{x+5} \] if x is less than 5, for example 6 we would have \[ \sqrt{6+5}= \sqrt{1} \] and we do not allow taking the square root of a negative number so we now know \( x\le 5\) is not allowed what is allowed is \( x \gt 5\) next, look at the top \[ \sqrt{5x}\] if x is bigger than 5, we will get a negative number inside the square root, and that is not allowed. so x must be less than or equal to 5 we have \[ 5 \lt x \le 5\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok thanls so much @Nnesha

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0For helping me understand the problem thanks @Nnesha
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