anonymous
  • anonymous
Will Fan and Medal!!! (√5-x) --------- = ????? (√x+5)
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
no0 the answer choices are A. {x|x<5}
1 Attachment
anonymous
  • anonymous
^^ the attachment are the answer choices
anonymous
  • anonymous
@pooja195 we need you

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

Jhannybean
  • Jhannybean
is your function: \(\dfrac{\sqrt{5-x}}{\sqrt{x+5}}\) ?
anonymous
  • anonymous
yes
Jhannybean
  • Jhannybean
\[\frac{\sqrt{5-x}\cdot \sqrt{x+5}}{\sqrt{x+5} \cdot \sqrt{x+5}}\]\[=\frac{\sqrt{25-x^2}}{x+5}\]
Jhannybean
  • Jhannybean
Im not too sure what you're looking for. Maybe you can specify your question. Are we looking for where x has a vertical asymptote?
anonymous
  • anonymous
idk i just have the questiona dn the answers
anonymous
  • anonymous
Here is the whole thing
1 Attachment
anonymous
  • anonymous
@Jhannybean
anonymous
  • anonymous
@ganeshie8
anonymous
  • anonymous
@Jhannybean @phi @Nnesha @ganeshie8 plz help
millsemily
  • millsemily
Hold on
anonymous
  • anonymous
@millsemily ok @ganeshie8 help?
phi
  • phi
the domain are the "x" values you can use in your function and get a valid answer out. You can run into trouble if you divide by 0 (that is not allowed) or taking the square root of a negative number (that is not allowed, if we want real numbers for the answer) Normally, we would figure out what x values will cause trouble, and "not allow them" what is left over is the domain.
phi
  • phi
First, look at the bottom \[ \sqrt{x+5} \] if that is 0, we would be dividing by 0 , and we don't allow that. notice if x=-5 we get sqr(0)= 0. we x=-5 is not allowed
phi
  • phi
still looking at the bottom: \[ \sqrt{x+5} \] if x is less than -5, for example -6 we would have \[ \sqrt{-6+5}= \sqrt{-1} \] and we do not allow taking the square root of a negative number so we now know \( x\le -5\) is not allowed what is allowed is \( x \gt -5\) next, look at the top \[ \sqrt{5-x}\] if x is bigger than 5, we will get a negative number inside the square root, and that is not allowed. so x must be less than or equal to 5 we have \[ -5 \lt x \le 5\]
anonymous
  • anonymous
ok thanls so much @Nnesha
Nnesha
  • Nnesha
what ??? o.O
anonymous
  • anonymous
For helping me understand the problem thanks @Nnesha

Looking for something else?

Not the answer you are looking for? Search for more explanations.