anonymous
  • anonymous
Solve for x. −ax + 3b > 5 x > the quantity 3 times b minus 5 all over a x > the quantity 5 minus 3 times b all over negative a x < the quantity 3 times b plus 5 all over a x < the quantity negative 3 times b plus 5 all over negative a
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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misty1212
  • misty1212
hi!!
misty1212
  • misty1212
i will provide the answer for you so long as you tell me where this question comes from (my guess FLVS)
gibbs
  • gibbs
x<−5−3b/a

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misty1212
  • misty1212
because in fact you cannot solve an absolute value inequality with variable coefficients
misty1212
  • misty1212
@gibbs is straight up wrong
anonymous
  • anonymous
Its from FLVS @misty1212
misty1212
  • misty1212
ok lets solve it the way they want you to, even though it is wrong
anonymous
  • anonymous
ok
misty1212
  • misty1212
\[−ax + 3b > 5\] subtract \(3b\) get \[-ax>5-3b\] then divide by \(-a\)
misty1212
  • misty1212
now here is the mistake they want you to change the inequality, because they want you to think that \(-a\) is negative that is sheer nonsense you do not know if \(-a\) is negative or positive
misty1212
  • misty1212
in any case they want you to write \[x<\frac{5-3b}{-a}\] or \[x<\frac{3b-5}{a}\]
misty1212
  • misty1212
it is totally incorrect, you should write them and tell them that anyone who thinks \(-a\) is negative (because it has a minus sign) does not understand what a variable is and has no business trying to teach math or write math questions
anonymous
  • anonymous
My answers ar this though... x > the quantity 3 times b minus 5 all over a x > the quantity 5 minus 3 times b all over negative a x < the quantity 3 times b plus 5 all over a x < the quantity negative 3 times b plus 5 all over negative a @misty1212

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