anonymous
  • anonymous
∆ABC is reflected about the line y = -x to give ∆A'B'C' with vertices A'(-1, 1), B'(-2, -1), C(-1, 0). What are the vertices of ∆ABC? A(1, -1), B(-1, -2), C(0, -1) A(-1, 1), B(1, 2), C(0, 1) A(-1, -1), B(-2, -1), C(-1, 0) A(1, 1), B(2, -1), C(1, 0) A(1, 2), B(-1, 1), C(0, 1)
Mathematics
katieb
  • katieb
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mathmate
  • mathmate
Use the transformation for reflection about y=-x s'(x,y): (x,y) -> (-y,-x) and the inverse transformation is the identical (as is true with all reflections) \((s')^{-1} : (x,y) -> (-y,-x)\) For example, a point P(5,2) is reflected about y=-x, then P' is P'(-2,-5) Calculate A, B, C point by point from the transformation of A', B', C' and you would find the answer in very little time.
anonymous
  • anonymous
i still am not understanding....what would the answer be ... @mathmate
anonymous
  • anonymous
i think it would be A(1, 2), B(-1, 1), C(0, 1) right

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anonymous
  • anonymous
err no it would be A(-1, 1), B(1, 2), C(0, 1)....
mathmate
  • mathmate
Please read the example showing you how to do the transformation? The transformation is (x,y) ->(-y,-x) so (5,2)->(-2,-5) Another example: If P' is P'(4,-3), the P after transformation is P(3,-4). Remember, in math, if you do not understand, ask how it works. Guessing game is a game for life, you'll never get anywhere.
mathmate
  • mathmate
Yes, A(-1, 1), B(1, 2), C(0, 1). is correct. Well done!
anonymous
  • anonymous
thank you
mathmate
  • mathmate
You're welcome! :)

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