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anonymous
 one year ago
∆ABC is reflected about the line y = x to give ∆A'B'C' with vertices
A'(1, 1), B'(2, 1), C(1, 0). What are the vertices of ∆ABC?
A(1, 1), B(1, 2), C(0, 1)
A(1, 1), B(1, 2), C(0, 1)
A(1, 1), B(2, 1), C(1, 0)
A(1, 1), B(2, 1), C(1, 0)
A(1, 2), B(1, 1), C(0, 1)
anonymous
 one year ago
∆ABC is reflected about the line y = x to give ∆A'B'C' with vertices A'(1, 1), B'(2, 1), C(1, 0). What are the vertices of ∆ABC? A(1, 1), B(1, 2), C(0, 1) A(1, 1), B(1, 2), C(0, 1) A(1, 1), B(2, 1), C(1, 0) A(1, 1), B(2, 1), C(1, 0) A(1, 2), B(1, 1), C(0, 1)

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mathmate
 one year ago
Best ResponseYou've already chosen the best response.2Use the transformation for reflection about y=x s'(x,y): (x,y) > (y,x) and the inverse transformation is the identical (as is true with all reflections) \((s')^{1} : (x,y) > (y,x)\) For example, a point P(5,2) is reflected about y=x, then P' is P'(2,5) Calculate A, B, C point by point from the transformation of A', B', C' and you would find the answer in very little time.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i still am not understanding....what would the answer be ... @mathmate

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i think it would be A(1, 2), B(1, 1), C(0, 1) right

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0err no it would be A(1, 1), B(1, 2), C(0, 1)....

mathmate
 one year ago
Best ResponseYou've already chosen the best response.2Please read the example showing you how to do the transformation? The transformation is (x,y) >(y,x) so (5,2)>(2,5) Another example: If P' is P'(4,3), the P after transformation is P(3,4). Remember, in math, if you do not understand, ask how it works. Guessing game is a game for life, you'll never get anywhere.

mathmate
 one year ago
Best ResponseYou've already chosen the best response.2Yes, A(1, 1), B(1, 2), C(0, 1). is correct. Well done!
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