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anonymous
 one year ago
Find x in this 45°45°90° triangle.
anonymous
 one year ago
Find x in this 45°45°90° triangle.

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FireKat97
 one year ago
Best ResponseYou've already chosen the best response.1You can use trig for this, think of the info you have, you're given an angle and the magnitude of the "hypotenuse" and want to find the "opposite" side think about SOHCAHTOA so Sin O, H Cos  A, H Tan O, A

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0How do I put SOHCAHTOA into this?

FireKat97
 one year ago
Best ResponseYou've already chosen the best response.1so you have been given the hypotenuse and want to find the opposite side, so you're using H and O, think of what H and O belong to, sin, cos or tan?

FireKat97
 one year ago
Best ResponseYou've already chosen the best response.1yup, so now try and apply sin, show me how you would set up an equation with sin and the info given

mathmate
 one year ago
Best ResponseYou've already chosen the best response.0It is very important to know the ratios sin, cos and tangent in general. However, it is equally important to know the properties of two very special triangles, 1. the isosceles right triangle, and the 2. 306090 triangle. In my opinion, we should be familiar with the properties of these two triangles to the point that we can recognize them as soon as we see one. 1. The isosceles right triangle dw:1443190596255:dw some properties:  measure of the legs (i.e. not hypotenuse) are equal  meausre of hypotenuse is sqrt(2)*length of a leg  conversely, measure of a leg is (sqrt(2)/2) of the hypotenuse.  obtuse angles are both 45. 2. The 306090 triangle dw:1443190812224:dw some properties  the median through the 90 degree angle divides the triangle into two triangles, one equilateral, and the other isosceles 3030120.  measure of hypotenuse is double that of side.  measure of the long leg is sqrt(3)x where x is the length of the short leg.
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