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nthenic_oftime

  • one year ago

any help would be great :) ... If the force acting on an object stays the same, then the acceleration of the object is inversely proportional to its mass. If an object with a mass of 9 kilograms accelerates at a rate of 6 meters per second per second by a force, find the rate of acceleration of an object with a mass of 2 kilograms that is pulled by the same force. A. 3 meters per second per second B. 27 meters per second per second C. 18 meters per second per second D. 24 meters per second per second

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  1. baru
    • one year ago
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    hi

  2. nthenic_oftime
    • one year ago
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    hello @baru

  3. welshfella
    • one year ago
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    Use Newtons second law of motion Force = mass * acceleration

  4. nthenic_oftime
    • one year ago
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    D?

  5. baru
    • one year ago
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    @nthenic_oftime have you started with physics...or is this a problem from math class?

  6. nthenic_oftime
    • one year ago
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    @baru i know some physics bt this is from math

  7. welshfella
    • one year ago
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    F = 9*6 = 54 N for the mass of 2 kg:- 54 = 2 a

  8. nthenic_oftime
    • one year ago
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    thank you @welshfella

  9. welshfella
    • one year ago
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    sole for a

  10. welshfella
    • one year ago
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    yw

  11. nthenic_oftime
    • one year ago
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    wait wouldnt i have to do 2*6 because its asking for object with mass of 2kg at same force

  12. welshfella
    • one year ago
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    the force is 54 N 6 is the acceleration for the 9 kg mass

  13. welshfella
    • one year ago
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    acceleration for 2 kg mass = 54/2

  14. baru
    • one year ago
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    @welshfella i think this is an exercise in ratios...not physics..he/she is not very familiar with force

  15. nthenic_oftime
    • one year ago
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    ooh okay get it we found the force first and then found rate of acceleration of the 2kg mass gotchya

  16. nthenic_oftime
    • one year ago
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    i dont understand why this is on a math test when to me it seems like physics

  17. welshfella
    • one year ago
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    well physics is often 'applied math'.

  18. baru
    • one year ago
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    you are supposed to understand how "inverse proportionality" works

  19. welshfella
    • one year ago
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    yea when a is inversely proportional to m we can write a = k / m where k is some constant in the above case the constant is the force (54)

  20. welshfella
    • one year ago
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    you can find the value of k by plugging in known values of a and m ( 6 and 9) 6 = k/9 so k = 6*9 = 54 know we have established the formula for a in terms of m a = 54/m so knowing the value of a or m we can find the other variable

  21. welshfella
    • one year ago
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    so when m = 2 a = 54/ 2

  22. nthenic_oftime
    • one year ago
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    okay @welshfella thats what i was seeing in my mind or what made sense i didnt know it had a name thank you for that info too

  23. nthenic_oftime
    • one year ago
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    lol

  24. welshfella
    • one year ago
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    with inverse variation as one variable increses the other decreases and vice versa

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