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pick a element and i will help
i did this 3 years ago lol
So i only need one element?
yes u need to pick one any one thru 1-7a on periodic table
I think this is a element; Malleable
make this easy
hydrogen melting: -259.14 °C boiling: -252.87 °C to find it in degrees F, multiply by 1.8 and then add 32. Hydrogen, with the chemical symbol H, is the chemical element with the atomic number 1.
Hydrogen has 1 as its atomic number. That's because it has one proton in its nucleus. Hydrogen has three isotopes. Each isotope has one proton in its nucleus (naturally, because that's what makes it hydrogen). Atomic mass is the number of protons plus the number of neutrons in an atom's nucleus. Let's look at each isotope of hydrogen. "Simple" hydrogen has only the 1 proton in its nucleus. It's atomic number is 1 and its mass number is 1 (the 1 proton plus zero neutrons). Heavy hydrogen has 1 proton and 1 neutron in its nucleus. It's atomic number is 1 and its mass number is 2 (the 1 proton plus 1 neutron). Heavy, heavy hydrogen has 1 proton and 2 neutrons in its nucleus. It's atomic number is 1 and its mass number is 3 (the 1 proton plus 2 neutrons).
So those are all the answers?
Name: Hydrogen Symbol: H Atomic Number: 1 Atomic Mass: 1.00794 amu Melting Point: -259.14 °C (14.009985 K, -434.45203 °F) Boiling Point: -252.87 °C (20.280005 K, -423.166 °F) Number of Protons/Electrons: 1 Number of Neutrons: 0 Classification: Non-metal Crystal Structure: Hexagonal Density @ 293 K: 0.08988 g/cm3 Color: colorless
almost u still need to get a pic of what the symbol looks like
Thank you so much! Were you in connxeus?
Hydrogen has an electronegativity value of 2.1
yes i was in there 3 years
go thru and see what else u still need and let me know
So what you sent me is all i need for the attachment i sent you?
. With an atomic weight of 1.00794 u,
i am picking thru and giving u answers u need to check them off and see what else is needed.. i cant do all the work for u :)
figuring it out
Electronegativity value • Atomic radius • Ionic radius • First ionization energy I still need these.
hold on a sec
Okay. thank you! for the line graph do i actually have to do one?
Atomic Radius: 0.79Å
Ionic Radius: 0.012Å
I.E of hydrogen is 1310 kJ/mol first ionaztion energy
Electronegativity value 2
that should be the last of it
Thank you! But do i need to do the line graph?
i didnt do a line graph
i wrote mine in excel format
Wow. I can't believe you just did their whole assignment for them.
lol you need to format is alittle better dont turn it in like that space them out i guess kinda like a chart with name description and so on
@thadyoung thats what happens when u get bored and know what ur doing lol
What did they learn? nothing.
that is true... he probably learned nothing, but how to get the answers :(
nice i was agreeing with you that i should have made this person work harder to figure it out
you cant say whatever because if you needed help you prob would of done the same thing. She needed help and she helped her. Get over yourself and move on.
Okay, i'm sorry @Missiey for not working hard. I was not trying to take advantage of you or your work. Thank you for you help.
nonsense dont listen to people on here.. its like they have nothing better to do than complain.. you needed help and i gave it..
and in the future if u need help just tag me. i will come and help you!!!!!!
Oky. Thank you so much. i appreciate that. Your the boom.
And thanks @hannahnichole12 for being sweet and helping with that guy.
ok im attaching a drawing not the best lol across top hydrogen w= weight m=mass and so on |dw:1443201177502:dw|
So i can just draw it on paper and take a pic and sent it to her from there?
no use excel
Okay! let me try it out?
How did you draw the lines?
do u have excel program on ur computer
see if that helps
I'm trying it and seeing it.
how are doing
I am doing good. thank you!
I am done with the lines i just have to do the paragraphs now.
perfect make sure u put all the data in rows and add the symbol for hydrogen on it.. good job
Thank you couldn't do it w/o you.
no problem.. i said i would help
And that is greatly appreciate that.